严格比较 [英] Strict comparison

问题描述

在 javascript 中，有严格的比较运算符 op1 === op2 和 op1 !== op2 将比较类型和值.有没有一种pythonic的方式来实现同样的事情?

In javascript, there are strict comparison operators op1 === op2 and op1 !== op2 that will compare both type and value. Is there a pythonic way of achieving the same thing?

到目前为止，我只能想出以下凌乱的条件:

So far I've only been able to come up with the following messy conditionals:

isinstance(op1, type(op2)) and isinstance(op2, type(op1)) and op1 == op2

和

not isinstance(op1, type(op2)) or not isinstance(op2, type(op1)) or op1 != op2

推荐答案

您的方法确实会检查值和类型.Python 中没有不同的运算符.

Your approach would indeed check both value and type. There isn't a different operator in Python.

话虽如此，在很多情况下这不是您想要的 - 在 Python 的哲学中，任何表现得像鸭子的对象都应该被视为鸭子.您通常不仅需要字典，还需要类似映射"的对象等等——只要该对象可以用于特定任务，那么代码就应该接受它.

This having been said, in many cases that's not what you want - in Python's philosophy any object that behaves as a duck should be treated as a duck. You often don't want only dictionaries, you want "mapping-like" objects and so on - as long as the object can be used for the particular task then the code should accept it.

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