jQuery的查找并替换数组 [英] jQuery find and replace with arrays

问题描述

我需要搜索的输入值各街道的缩写，用适当的后缀替换。这是我到目前为止有：

I need to search an input's value for all street abbreviations and replace with appropriate suffix. This is what I have so far:

jQuery('#colCenterAddress').val(function(i,val) {
    var f = ['Rd','St','Ave'];
    var r = ['Road','Street','Avenue'];
    return val.replace(f,r);
});

思考？

推荐答案

您需要遍历˚F阵列，并尝试每个单独更换。

You need to iterate the f Array, and try each replace separately.

jQuery('#colCenterAddress').val(function(i,val) {
    var f = ['Rd','St','Ave'];
    var r = ['Road','Street','Avenue'];
    $.each(f,function(i,v) {
        val = val.replace(new RegExp('\\b' + v + '\\b', 'g'),r[i]);
    });
    return val;
});

DEMO： http://jsfiddle.net/vRTNt/

如果这是你要定期做一些事情，你可能希望存储阵列，甚至使具有pre-做定期的前pressions第三阵列。

If this is something you're going to do on a regular basis, you may want to store the Arrays, and even make a third Array that has the pre-made regular expressions.

var f = ['Rd','St','Ave'];
var r = ['Road','Street','Avenue'];

var re = $.map(f, function(v,i) {
    return new RegExp('\\b' + v + '\\b', 'g');
});

jQuery('#colCenterAddress').val(function(i,val) {
    $.each(f,function(i,v) {
        val = val.replace(re[i],r[i]);
    });
    return val;
});

DEMO： http://jsfiddle.net/vRTNt/1/

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