查找数字并替换 + 1 [英] Find number and replace + 1

问题描述

我有一个大文件，其中包含一个页面递增的对象列表#ie

<预><代码>[{页面:1}，{第2页}，{页面:3}]

我可以在 vscode 的 ctrl+f 查找器中找到 page: # 和 page: (\d) 的每个实例.我将如何用 # + 1 替换这些数字中的每一个?

解决方案

无法使用正则表达式执行算术运算.我使用 LINQPad 来执行这些小脚本.下面的 c# 程序是我将如何做的一个示例.

void Main(){var basePath = @"C:\";//获取目录及其所有子目录中所有扩展名为 .cs 的文件.foreach (var filePath in Directory.GetFiles(basePath, "*.cs", SearchOption.AllDirectories)){//读取文件内容.var fileContent = File.ReadAllText(filePath);//使用命名的捕获组替换内容.//命名捕获组只允许使用正则表达式匹配的一部分.var replaceContent = Regex.Replace(fileContent, @"page: (?[0-9]+)", match => $"page: {int.Parse(match.Groups["number"].值) + 1}");//将替换的内容写回文件.File.WriteAllText(文件路径，替换内容)；}}

我还冒昧地将您的正则表达式更改为下面的那个.

page: (?[0-9]+)page: 与page:"字面匹配.(? 是一个名为 number 的命名捕获组的开始.然后我们可以在替换期间使用这个组.[0-9]+ 匹配 0 到 9 之间的数字一到无限次.这比使用 \d 更具体，因为 \d 也匹配其他数字字符.+ 使它比数字更匹配，允许数字 10 及以后的数字.) 是命名捕获组的结尾.

I have a large file with a list of objects that have an incrementing page # ie

[
{page: 1},
{page: 2},
{page: 3}
]

I can find each instance of page: # with page: (\d) in vscode's ctrl+f finder. How would I replace each of these numbers with # + 1?

解决方案

It's not possible to perform arithmetic with regex. I use LINQPad to execute these small kind of scripts. An example of how I would do it is in the c# program below.

void Main()
{
    var basePath = @"C:\";

    // Get all files with extension .cs in the directory and all its subdirectories.
    foreach (var filePath in Directory.GetFiles(basePath, "*.cs", SearchOption.AllDirectories))
    {
        // Read the content of the file.
        var fileContent = File.ReadAllText(filePath);

        // Replace the content by using a named capture group.
        // The named capture group allows one to work with only a part of the regex match.
        var replacedContent = Regex.Replace(fileContent, @"page: (?<number>[0-9]+)", match => $"page: {int.Parse(match.Groups["number"].Value) + 1}");

        // Write the replaced content back to the file.
        File.WriteAllText(filePath, replacedContent);
    }
}

I also took the liberty of changing your regex to the one below.

page: (?<number>[0-9]+)

page:  matches with "page: " literally.
(?<number> is the start of a named capture group called number. We can then use this group during replacement.
[0-9]+ matches a number between 0 and 9 one to infinite times. This is more specific than using \d as \d also matches other number characters.
The + makes it match more than on digit allowing for the number 10 and onwards.
) is the end of a named capture group.

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