按定义的间隔切割 [英] Cut by Defined Interval

问题描述

R 中是否有某种方法可以在不中断的情况下按定义的间隔进行切割?

Is there some way in R to cut by a defined interval without any breaks?

例如，如果我想要精确间隔 [1,10] 中的值；默认情况下，cut 将这个区间分成更小的区间.

For example, if I want the values in the exact interval [1,10]; by default cut breaks this interval into smaller intervals.

推荐答案

要剪切到预定义的间隔，您可以使用 breaks 参数指定中断向量.

To cut unto pre-defined intervals, you can specify a vector of breaks using the breaks parameter.

定义一些数据:

x <- sample(0:20, 100, replace=TRUE)
x

现在在 0、10 和 20 处切割 x:

Now cut x at 0, 10 and 20:

cut(x, breaks=c(0, 10, 20), include.lowest=TRUE)

  [1] (10,20] [0,10]  [0,10]  (10,20] (10,20] (10,20] [0,10]  (10,20] (10,20]
 [10] (10,20] [0,10]  (10,20] (10,20] (10,20] [0,10]  (10,20] [0,10]  [0,10] 
 [19] [0,10]  (10,20] [0,10]  [0,10]  [0,10]  (10,20] [0,10]  (10,20] (10,20]
 [28] (10,20] (10,20] [0,10]  [0,10]  [0,10]  [0,10]  (10,20] [0,10]  [0,10] 
 [37] [0,10]  [0,10]  (10,20] (10,20] (10,20] (10,20] [0,10]  (10,20] [0,10] 
 [46] (10,20] [0,10]  (10,20] (10,20] [0,10]  [0,10]  (10,20] (10,20] (10,20]
 [55] [0,10]  [0,10]  (10,20] [0,10]  [0,10]  [0,10]  [0,10]  (10,20] (10,20]
 [64] (10,20] [0,10]  [0,10]  (10,20] (10,20] (10,20] (10,20] (10,20] (10,20]
 [73] (10,20] [0,10]  [0,10]  [0,10]  (10,20] [0,10]  (10,20] [0,10]  (10,20]
 [82] [0,10]  [0,10]  (10,20] [0,10]  [0,10]  [0,10]  (10,20] (10,20] [0,10] 
 [91] [0,10]  [0,10]  (10,20] (10,20] [0,10]  [0,10]  [0,10]  [0,10]  (10,20]
[100] (10,20]
Levels: [0,10] (10,20]

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