如何将向量或列切割成R中的间隔 [英] How to cut a vector or column into intervals in R

问题描述

我在数据框中有以下列，每行之间的差异为 0.012 秒:

I have the following columns in a dataframe which difference between each row is 0.012 s :

Time
 0
 0.012
 0.024
 0.036
 0.048
 0.060
 0.072
 0.084
 0.096
 0.108

我想从开始的时间间隔开始增加 0.030，因此以后每 0.03 的时间间隔或时间窗口将用于分组.

I want to come up with intervals starting from beginning increasing by 0.030, so intervals or time window of every 0.03 later to be used in group by.

推荐答案

你可以试试findInterval like

findInterval(df$Time, seq(min(df$Time), max(df$Time), 0.03))
#[1] 1 1 1 2 2 3 3 3 4 4

我们也可以使用cut

breaks <- seq(min(df$Time), max(df$Time), 0.03)
cut(df$Time, c(breaks, Inf), labels = breaks, include.lowest = TRUE)
#[1] 0    0    0    0.03 0.03 0.03 0.06 0.06 0.09 0.09

数据

df <- structure(list(Time = c(0, 0.012, 0.024, 0.036, 0.048, 0.06, 
0.072, 0.084, 0.096, 0.108)), class = "data.frame", row.names = c(NA, -10L))

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