如何将向量或列切成R中的间隔 [英] How to cut a vector or column into intervals in R

问题描述

我在数据框中有以下几列，每行之间的差为0.012 s:

I have the following columns in a dataframe which difference between each row is 0.012 s :

Time
 0
 0.012
 0.024
 0.036
 0.048
 0.060
 0.072
 0.084
 0.096
 0.108

我想计算从开始增加0.030的间隔，因此以后每0.03的间隔或时间窗口将在分组依据中使用.

I want to come up with intervals starting from beginning increasing by 0.030, so intervals or time window of every 0.03 later to be used in group by.

推荐答案

您可以尝试 findInterval 之类的

findInterval(df$Time, seq(min(df$Time), max(df$Time), 0.03))
#[1] 1 1 1 2 2 3 3 3 4 4

我们也可以使用 cut

breaks <- seq(min(df$Time), max(df$Time), 0.03)
cut(df$Time, c(breaks, Inf), labels = breaks, include.lowest = TRUE)
#[1] 0    0    0    0.03 0.03 0.03 0.06 0.06 0.09 0.09

数据

df <- structure(list(Time = c(0, 0.012, 0.024, 0.036, 0.048, 0.06, 
0.072, 0.084, 0.096, 0.108)), class = "data.frame", row.names = c(NA, -10L))

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