C：发现元素的数量在阵列[] [英] C: finding the number of elements in an array[]

问题描述

在C：
如何找到的元素数在结构的数组，把它发送给一个函数之后

In C: How do you find the number of elements in an array of structs, after sending it to a function?

int main(void) {
  myStruct array[] = { struct1, struct2, struct3, struct4, struct5, struct6 };
  printf("%d\n", sizeof(array));
  printf("%d\n", sizeof(array[0]));
  f(array);
}
void f(myStruct* array) {
  printf("%d\n", sizeof(array));
  printf("%d\n", sizeof(array[0]));
}

由于某种原因主要在与printf显示出比F中的printf不同的结果。
我需要的是知道有多少元素数组中

For some reason the printf in main shows different results than the printf in f. My need is to know how many elements are in the array.

推荐答案

您不能。

您必须将大小传递给函数，例如：

You have to pass the size to the function, eg:

void f(myStruct* array, size_t siz);

另请注意，在˚F数组是一个指针，而在主它是一个数组。数组和指针是不同的东西。

Also notice that in f array is a pointer, while in main it is an array. Arrays and pointers are different things.

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