在Python的组合生成 [英] Generating Combinations in python
问题描述
我不知道如何去这在Python,如果甚至有可能。我需要做的就是创建3个独立的数组的数组(或矩阵,或矢量?)。每个阵列为4元素,例如,它们返回这样:
I am not sure how to go about this in Python, if its even possible. What I need to do is create an array (or a matrix, or vector?) from 3 separate arrays. Each array as 4 elements as such, they return this:
的Class1 = [1,2,3,4]
等级2 = [1,2,3,4]
在Class3 = [1,2,3,4]
Class1 = [1,2,3,4] Class2 = [1,2,3,4] Class3 = [1,2,3,4]
现在我想做的是回到这三个类的所有可能的组合是什么。
Now what I would like to do is return all possible combinations of these three classes.
例如:
1 1 1结果
2 1 1结果
3 1 1结果
4 1 1结果
1 2 1搜索
2 2 1结果
3 2 1结果
4 2 1 ...
1 1 1
2 1 1
3 1 1
4 1 1
1 2 1
2 2 1
3 2 1
4 2 1...
...等,以64行(4元素*为每个类16种可能的组合= 64行
...and so on to 64 rows (4 elements *16 possible combinations for each class = 64 rows
我希望有一种方法在Python做到这一点。我肯定是有的,但我不知道最有效的方式去将是什么。也许为循环语句在每一类中的每个元素进行迭代?还是现在,我研究这个,就和itertools处理呢?
I am hoping there is a way to do this in python. I am sure there is but I am not sure what the most efficient way to go about would be. Perhaps a "for in" loop statement that iterates over each element for each class? Or now that I am researching this, would itertools handle this?
在此先感谢提供任何帮助。
Thanks in advance for any help offered.
推荐答案
你想要什么叫做笛卡尔产品:
import itertools
iterables = [ [1,2,3,4], [88,99], ['a','b'] ]
for t in itertools.product(*iterables):
print t
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