在结构之间复制属性 [英] Copy properties between structs

问题描述

有没有办法比较两个不同结构的两个实例，如果有完全相同名称的属性，是否将它们从一个实例复制到另一个实例?

Is there a way to compare two instances of two different structs and if there are properties with the exact same name, have them copied from one instance to the other?

以两个结构体为例:

struct typeA
{
 public byte ID;
 public byte distance;
 public byte time;
}

struct typeB
{
 public byte distance;
 public byte length;
}

然后创建变量

 typeA A;
 typeB B;

接下来分配一些值

 A.ID = 101;
 A.distance = 12;
 A.time = 5;

现在我想将变量 A 与 B 进行比较，如果有任何具有相同名称的属性(在这种情况下，两个结构都存在距离")，将它们复制到另一个变量.我不想用

Now I want to compare variable A with B and if there are any properties with the same name (in this case 'distance' exist for both struct) copy them to the other variable. I don't want to use

 B.distance = A.distance

因为我不会总是知道属性的名称.

as I won't always know the names of the properties.

有人有什么想法吗?只听说过 Reflection，可以看看吗?

Does anybody have any ideas? Have only heard of Reflection, is that something to have a look at?

推荐答案

我建议您为此使用映射工具.例如.AutoMapper(可从 NuGet 获得)

I suggest you to use mapping tool for this. E.g. AutoMapper (avalable from NuGet)

Mapper.CreateMap<typeA, typeB>();
typeA A = new typeA { ID = 101, distance = 12, time = 5 };
typeB B = new typeB { length = 42 };
// ...
B = Mapper.Map(A, B);

使用默认映射 AutoMapper 将映射具有相同名称的属性.

With default mapping AutoMapper will map properties which have same names.

您应该将映射结果分配回 B 变量，因为结构体是值类型并且它们按值传递.因此，对 B 传递副本的更改不会影响原始 B 变量.上面代码的结果是带有值的变量 B:

You should assign result of mapping back to B variable, because structs are value types and they passed by value. So, changes to passed copy of B will not affect original B variable. Result of code above is variable B with values:

{
  distance: 12,
  length: 42
}

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