在函数C ++之间传递结构 [英] Passing struct between functions C ++

问题描述

我已搜索，但未能获得我想要的内容...

I've searched but haven't been able to get what I want...

我在做一个小游戏。我得到了包含播放器详细信息的 struct 。

I'm doing a little game. And I got this struct that contains the player details.

struct Player
{
    string name;
    int level;
    int exp;
    int hp; // life
    int mp; // mana
    int shield;
};

在菜单中，用户选择开始一个新游戏，

And when in the menu, the user chooses to start a new game, it goes to this function:

    int StartNewPlayer(string name)
    {
        Player player;

        player.name = name;
        player.level = 1;
        player.exp = 0;
        player.hp = 20;
        player.mp = 5;
        player.shield = 0;

        *pass/return the struct here*
    }

然后我有一个函数打印游戏板，我应该使用新的播放器结构的数据，例如：

Then I have a function that prints the game board, and where I should use the data from the new player struct, for example:

void game_board ()
{
    cout << "Hello!" << player.name;

    (...)
}

在 main 我有：

int main ()
{
    StartNewPlayer(new_game());
    game_board();
}

调用上述所有函数。

但我不能弄清楚...我试着参考，指针没有运气..我需要一些帮助这里请...

But I can't figure it out... I tried references, pointers without luck.. I need some help here please...

推荐答案

这是怎么回事？

Player StartNewPlayer(string name)
{
    Player player;

    player.name = name;
    player.level = 1;
    player.exp = 0;
    player.hp = 20;
    player.mp = 5;
    player.shield = 0;

    return player;
}

void game_board(Player player)
{
    cout << "Hello!" << player.name;

    (...)
}

int main ()
{
    Player player = StartNewPlayer(new_game());
    game_board(player);
}

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