正则表达式匹配具有唯一(非重复)字符的单词 [英] regex to match a word with unique (non-repeating) characters

问题描述

我正在寻找一个正则表达式，它仅在所有字符都是唯一的情况下才匹配一个单词，意思是，单词中的每个字符只出现一次.

I'm looking for a regex that will match a word only if all its characters are unique, meaning, every character in the word appears only once.

示例:
abcdefg -> 将返回 MATCH
abcdefgbh -> 将返回 NO MATCH(因为字母 b 重复多次)

Example:
abcdefg -> will return MATCH
abcdefgbh -> will return NO MATCH (because the letter b repeats more than once)

推荐答案

试试这个，可能有用，

^(?:([A-Za-z])(?!.*\1))*$

说明

Assert position at the beginning of a line (at beginning of the string or after a line break character) «^»
Match the regular expression below «(?:([A-Z])(?!.*\1))*»
   Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
   Match the regular expression below and capture its match into backreference number 1 «([A-Z])»
      Match a single character in the range between "A" and "Z" «[A-Z]»
   Assert that it is impossible to match the regex below starting at this position (negative lookahead) «(?!.*\1)»
      Match any single character that is not a line break character «.*»
         Between zero and unlimited times, as many times as possible, giving back as needed (greedy) «*»
      Match the same text as most recently matched by capturing group number 1 «\1»
Assert position at the end of a line (at the end of the string or before a line break character) «$»

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