Vim 正向前瞻正则表达式 [英] Vim positive lookahead regex

问题描述

我仍然不太习惯 vim 正则表达式语法.我有这个代码:

I am still not so used to the vim regex syntax. I have this code:

rename_column :keywords, :textline_two_id_4, :textline_two_id_4

我想将最后一个 id 与 VIM 正则表达式语法中的正向前瞻相匹配.

I would like to match the last id with a positive lookahead in VIMs regex syntax.

你会怎么做?

\id@=_\d$

这不起作用.

这个 perl 语法有效:

This perl syntax works:

id(?=_\d$)

编辑 - 答案:

/id\(_\d$\)\@=

谁能解释一下语法?

推荐答案

如果查看 vim 帮助，没有太多说明:(:h \@=)

If you check the vim help, there is not much to explain: (:h \@=)

\@=     Matches the preceding atom with zero width. {not in Vi}
        Like "(?=pattern)" in Perl.
        Example             matches
        foo\(bar\)\@=       "foo" in "foobar"
        foo\(bar\)\@=foo    nothing

这应该与最后一个 id 匹配:

This should match the last id:

/id\(_\d$\)\@=

用非常神奇"保存一些反斜杠:

save some back slashes with "very magic":

/\vid(_\d$)@=

其实用vim的\zs\ze看起来更直接:

actually, it looks more straightforward to use vim's \zs \ze:

id\ze_\d$

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