使用通配符或正则表达式在字符串末尾查找空格 [英] Find whitespace in end of string using wildcards or regex

问题描述

我有一个 Resoure.resx 文件，我需要搜索以查找以空格结尾的字符串.我注意到在 Visual Web Developer 中，我可以使用正则表达式和通配符进行搜索，但我无法弄清楚如何最终只找到带有空格的字符串.我试过这个正则表达式但没有用:

I have a Resoure.resx file that I need to search to find strings ending with a whitespace. I have noticed that in Visual Web Developer I can search using both regex and wildcards but I can not figure out how to find only strings with whitespace in the end. I tried this regex but didn't work:

\s$

你能举个例子吗?谢谢！

Can you give me an example? Thanks!

推荐答案

我希望它可以工作，尽管因为 \s 包括 \n 和 \r，也许它变得混乱了.或者我认为它可能(但真的不太可能)Visual Web Developer 使用的正则表达式的风格(我没有副本)没有 \s 字符类.试试这个:

I'd expect that to work, although since \s includes \n and \r, perhaps it's getting confused. Or I suppose it's possible (but really unlikely) that the flavor of regular expressions that Visual Web Developer uses (I don't have a copy) doesn't have the \s character class. Try this:

[ \f\t\v]$

...搜索行尾的空格、换页、制表符或垂直制表符.

...which searches for a space, formfeed, tab, or vertical tab at the end of a line.

如果您正在执行搜索和替换操作，并希望去掉行尾的所有空格，则 正如 RageZ 指出的，您需要包含一个贪婪的量词(+ 表示一个或多个")，以便您尽可能多地获取:

If you're doing a search and replace and want to get rid of all of the whitespace at the end of the line, then as RageZ points out, you'll want to include a greedy quantifier (+ meaning "one or more") so that you grab as much as you can:

[ \f\t\v]+$

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