如何编写搜索模式以在 findstr 中包含空格? [英] How to write a search pattern to include a space in findstr?

问题描述

我想在某个目录中的所有文件中搜索诸如

I want to search all files in a certain directory for occurrences of statements such as

  Load frmXYZ

我使用的是 Windows 7，使用 findstr 命令.我试过了:

I am on Windows 7, using the findstr command. I tried:

  findstr /n Load.*frm *.*

但这给了我不想要的结果，例如:

But this gives me unwanted results such as:

 If ABCFormLoaded Then Unload frmPQR

所以我尝试在 Load 和 frm 之间放置一个空格并给出如下命令:

So I tried to put a blankspace between Load and frm and gave the command like this:

 findstr /n Load frm *.*

但这只是搜索所有出现的词load 或所有出现的词frm.我该如何解决这个问题?

But this simply searched for all occurrences of the word load or all occurrences of the word frm. How do I get around this problem?

推荐答案

如果使用空格，则需要 /C: 选项将文字字符串传递给正则表达式 /R 选项.
一旦它到达正则表达式，它就会被视为正则表达式.

If you use spaces, you need the /C: option to pass the the literal string(s) to the regex /R option.
Once the it gets to the regex, it's treated as a regex.

也就是说，这是典型的 MS 垃圾.

That said, this is typical MS trash.

最重要的是，您必须使用 2 个字符串来处理以下情况
Load frm 开头是这样的:

The bottom line is that you have to use 2 strings to handle cases where
Load frm is at the beginning like so:

• 加载苹果香蕉胡萝卜

或在中间像这样:

• 一些其他文本加载 frm 和更多.

下面是XP sp3，windows 7可能不一样，都是垃圾！

Below is using XP sp3, windows 7 may be different, both are trash!

findstr/N/R/C:" *Load *frm"/C:"^Load *frm" test.txt

7:Load frm is ok    
8:    Load     frm is ok  

注意冒号

注意:/C: 中的冒号是强制执行的.

Mind the Colon

NOTE: The colon in /C: is MANDATORY for this to work.

如果省略冒号，则 findstr 的错误处理只是将 /C 视为无效选项，忽略该无效选项并继续进行.导致意外和不需要的输出.

If you leave out the colon then findstr's error handling is just to treat /C as an invalid option, ignore that invalid option and go ahead anyway. Leading to unexpected and unwanted output.

findstr/N/R/C:"[ ][ ]*Load[ ][ ]*frm"/C:"^Load[ ][ ]*frm" test.txt >

字符类细分

// The first regex search string breaks down like this:
[ ]   // require 1 space
[ ]*  // optional many spaces
Load  // literal 'Load'
[ ]   // require 1 space
[ ]*  // optional many spaces
frm   // literal 'frm'

// The second regex search string breaks down like this:
^     // beginning of line
Load  // literal 'Load'
[ ]   // require 1 space
[ ]*  // optional many spaces
frm   // literal 'frm'

真正的正则表达式可能是 \bLoad\s+frm

A real regex might be \bLoad\s+frm

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