[A-z0-9]+ 正则表达式匹配方括号 [英] [A-z0-9]+ regexp matching square brackets

问题描述

我正在为以下正则表达式苦苦挣扎

I'm struggling with the following regexp

[A-z0-9]+

如果针对此字符串进行测试:

If tested against this string:

||a919238[.--a]asd|

它返回a919238[，包括方括号..我试图输入我的测试用例在 regex101 上了解出了什么问题，但是站点 regex 解释没有帮助，可能我看不到我的错误.

it returns a919238[, including the square bracket.. I tried to input my test case on regex101 to understand what's wrong, but the site regex explanation is not helping, probably I'm not able to see my mistake.

为什么结果中包含方括号?

Why is the square bracket included in the result?

推荐答案

因为

[A-z0-9]+ 
 ↑ ↑ 

是从A到z，看ASCII表，]出现在两个字符之间:

is from A to z, see the ASCII table, ] appears between the two characters:

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