具有多个匹配项的正则表达式组捕获 [英] Regular expression group capture with multiple matches

问题描述

快速正则表达式问题.
我试图在 python 中捕获一个捕获组的多个实例(不要认为它是特定于 python 的)，但随后的捕获似乎覆盖了以前的.

Quick regular expression question.
I'm trying to capture multiple instances of a capture group in python (don't think it's python specific), but the subsequent captures seems to overwrite the previous.

在这个过于简化的例子中，我实际上是在尝试拆分一个字符串:

In this over-simplified example, I'm essentially trying to split a string:

x = 'abcdef'
r = re.compile('(\w){6}')
m = r.match(x)
m.groups()     # = ('f',) ?!?

我想得到 ('a', 'b', 'c', 'd', 'e', 'f')，但是因为正则表达式会覆盖后续的捕获，所以我得到 ('f',)

I want to get ('a', 'b', 'c', 'd', 'e', 'f'), but because regex overwrites subsequent captures, I get ('f',)

这是正则表达式应该表现的方式吗?有没有办法做我想做的事而不必重复六次语法?

Is this how regex is supposed to behave? Is there a way to do what I want without having to repeat the syntax six times?

提前致谢！
安德鲁

Thanks in advance!
Andrew

推荐答案

恐怕您不能为此使用群组.每个组只能匹配一次，我相信所有正则表达式都是这样工作的.一个可能的解决方案是尝试使用 findall() 或类似方法.

You can't use groups for this, I'm afraid. Each group can match only once, I believe all regexes work this way. A possible solution is to try to use findall() or similar.

r=re.compile(r'\w')
r.findall(x)
# 'a', 'b', 'c', 'd', 'e', 'f'

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