PHP preg_match 将花括号与其他类型的花括号不匹配.如何避免? [英] PHP preg_match is mismatching a curly apostrophe with other types of curly quotes. How to avoid?

问题描述

我有以下变量内容:

$content_content = '我做不到，她说."';

我想对其中的每个单词"进行 preg_match，包括缩写，所以我使用 preg_match 如下:

 if (preg_match_all('/([a-zA-Z0-9']+)/', $content_content, $matches)){echo '
';print_r($matches);echo '</pre>';}
然而，似乎通过在正则表达式中包含 ’，它也捕获了双引号，如上面的命令输出:
数组([0] =>大批([0] =>[1] =>一世[2] =>不能[3] =>做[4] =>它[5] =>她[6] =>说[7] =>)[1] =>大批([0] =>[1] =>一世[2] =>不能[3] =>做[4] =>它[5] =>她[6] =>说[7] =>))
如何在不包含和"的情况下包含 ’?
解决方案
这是因为您在字符集中使用的花哨"撇号是以二进制形式处理的；您需要使用其各自的 modifier 启用 Unicode 模式:
preg_match_all('/([a-zA-Z0-9']+)/u', $content_content, $matches)
演示
I have the following variable content:

$content_content = '"I can’t do it, she said."';

I want to do a preg_match for every "word" in that, including the contractions, so I use preg_match as follows:
 if (preg_match_all('/([a-zA-Z0-9’]+)/', $content_content, $matches))
 {
    echo '<pre>';
    print_r($matches);
    echo '</pre>';
 }
However, it seems by including ’ in the regular expression, it's also trapping the curly double quotes, as the above command outputs:
Array
(
    [0] => Array
        (
            [0] => ��
            [1] => I
            [2] => can’t
            [3] => do
            [4] => it
            [5] => she
            [6] => said
            [7] => ��
        )

    [1] => Array
        (
            [0] => ��
            [1] => I
            [2] => can’t
            [3] => do
            [4] => it
            [5] => she
            [6] => said
            [7] => ��
        )

)
How can I include ’ without it also including the " and "?
解决方案
This is because the "fancy" apostrophe you're using inside the character set is treated in its binary form; you need to enable Unicode mode using its respective modifier:
preg_match_all('/([a-zA-Z0-9’]+)/u', $content_content, $matches)
Demo

                        
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