获取父目录的相对路径 [英] Get relative path to a parent directory

问题描述

我有一个场景，我想获取返回特定父目录的路径.这是一个示例文件夹结构([something] 是一个文件夹)

I have a scenario where I want to get a path back to a specific parent directory. Here is an example folder strcuture ([something] is a folder)

index.php
[components]
    header.php
    footer.php
[pages]
    somePage.php
    [somePageSubPages]
        someSubPage.php

所以我的内容页面看起来像这样:

So my content pages look something like this:

<?php
    include('components/header.php');
?>

<!-- CONTENT STUFF -->

<?php
    include('components/footer.php');
?>

这适用于 index.php 但不适用于 somePage.php 和 someSubPage.php.我想要做的是创建一个函数，将路径返回到主目录，这样我就可以将其添加到包含和其他内容中:

This works for the index.php but not for somePage.php and someSubPage.php. What I want to do is create a function that returns the path back to the main directory so I can then add this to the includes and other stuff:

$relPath = getPathToRoot($rootDirName);
include($relPath . 'components/header.php');

而且该函数只会返回一个空字符串或../../.

And the function only would return an empty string or ../../.

我想过使用 __FILE__ 然后只计算给定 $rootDirName 和字符串结尾之间的 / 字符.但是，我想问一下这是否是一种可靠的方法以及它在 PHP 中的外观.(我对 PHP 的工作并不多......)

I thought about using __FILE__ and then just count the /-characters between the given $rootDirName and the the string end. However, I would like to ask if this is a reliable way and how this would look in PHP. (I don't realy work that much with PHP...)

推荐答案

可以使用..进入上级目录:

You can use .. to get into the parent directory:

<?php
    // somePage.php
    include('../components/header.php');
?>

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