传递对象的一个jQuery数组到PHP数组 [英] Passing a Jquery array of objects into a php array
问题描述
我在jQuery的一个数组,我尝试使用后转换为PHP数组:
$后(http://www.samepage.com,{final_slip:JSON.stringify(final_slip)})。
当我通过这个动态创建数组final_slip进去:
[final_bet_game {final_user_id =1,final_game_id =1,final_game_type =S pread_2,final_price =10,final_odds =1.8}, final_bet_game {final_user_id =2,final_game_id =3,final_game_type =S pread_2,final_price =1,final_odds =2.8},final_bet_game {final_user_id =3,final_game_id =14 ,final_game_type =S pread_32,final_price =140,final_odds =1.8},final_bet_game {final_user_id =4,final_game_id =1,final_game_type =S pread_2,final_price = 10,final_odds =2.8},]
我得到这个PHP的输出:
$数据= $ _ POST ['final_slip'];
的print_r($数据);[{\\\"final_user_id\\\":\\\"1\\\",\\\"final_game_id\\\":\\\"1\\\",\\\"final_game_type\\\":\\\"s$p$pad_2\\\",\\\"final_price\\\":\\\"211\\\",\\\"final_odds\\\":\\\"1.8\\\"},{\\\"final_user_id\\\":\\\"1\\\",\\\"final_game_id\\\":\\\"2\\\",\\\"final_game_type\\\":\\\"s$p$pad_2\\\",\\\"final_price\\\":\\\"212\\\",\\\"final_odds\\\":\\\"1.8\\\"},{\\\"final_user_id\\\":\\\"1\\\",\\\"final_game_id\\\":\\\"parlay\\\",\\\"final_game_type\\\":\\\"\\\",\\\"final_price\\\":\\\"021\\\",\\\"final_odds\\\":\\\"\\\"}]
我试图用json_decod,但是我没有得到任何结果。我怎样才能得到这一个可用的PHP数组?我会过得更好用ajax?
$后(http://www.samepage.com,{myJsonString:JSON.stringify(myJsonString)})。
但是,当我再尝试访问它在PHP中我没有看到任何结果。
块引用>和是的告诉你,你有另外一个问题 - 的 PHP没有报告错误的。你想转动
的error_reporting
上。在这种情况下,可能的原因是您的数据到达到
$ _ POST
阵列和$ myJsonString
没有定义(参数自动定义已经去precated 自PHP 5.3.0,并自PHP 5.4.0)不再可用您要么做
如果(array_key_exists('myJsonString',$ _ POST)){
$ myJsonString = $ _ POST ['myJsonString'];
}其他{
死(在不_POST myJsonString);
}或尝试直
$结果= json_de code($ _ POST ['myJsonString'],真实);
I have an array in jQuery that I am trying to convert to a PHP array by using Post:
$.post("http://www.samepage.com", {final_slip: JSON.stringify(final_slip)});
When I pass this dynamically created array "final_slip" into it :
[final_bet_game { final_user_id="1", final_game_id="1", final_game_type="spread_2",final_price="10", final_odds="1.8"}, final_bet_game { final_user_id="2", final_game_id="3", final_game_type="spread_2",final_price="1", final_odds="2.8"}, final_bet_game { final_user_id="3", final_game_id="14", final_game_type="spread_32",final_price="140", final_odds="1.8"}, final_bet_game { final_user_id="4", final_game_id="1", final_game_type="spread_2",final_price="10", final_odds="2.8"}, ]
I get this php outputted :
$data = $_POST['final_slip']; print_r ( $data); [{\"final_user_id\":\"1\",\"final_game_id\":\"1\",\"final_game_type\":\"spread_2\",\"final_price\":\"211\",\"final_odds\":\"1.8\"},{\"final_user_id\":\"1\",\"final_game_id\":\"2\",\"final_game_type\":\"spread_2\",\"final_price\":\"212\",\"final_odds\":\"1.8\"},{\"final_user_id\":\"1\",\"final_game_id\":\"parlay\",\"final_game_type\":\"\",\"final_price\":\"021\",\"final_odds\":\"\"}]
I tried to use the json_decod, but Im not getting any results. How can I get this to a usable php array? Would I be better off using ajax?
解决方案$.post("http://www.samepage.com", {myJsonString: JSON.stringify(myJsonString)});
But when I then try to access it in PHP I am not seeing any results.
And that tells you that you have another problem - PHP is not reporting errors. You want to turn
error_reporting
on.In this case the likely cause is that your data is arriving into the
$_POST
array, and$myJsonString
is not defined (automatic definition of parameters has been deprecated since PHP 5.3.0, and no longer available since PHP 5.4.0).You should either do
if (array_key_exists('myJsonString', $_POST)) { $myJsonString = $_POST['myJsonString']; } else { die("myJsonString not in _POST"); }
or try straight
$result = json_decode($_POST['myJsonString'], true);
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