传递一个动态的对象数组来运行 [英] Pass a dynamic array of objects to function

问题描述

我正在学习c ++。所以我知道一种方法，通过它你发送的东西功能，然后工作，如果它是按值调用，但实际上它是通过引用调用。例如

  void myFUNC（string& x）
  

现在，我有一个动态创建的对象数组。我想传递数组以像上面的方法一样工作。这是代码片段

  City * p = new City [number]; //指向动态类对象数组的指针
 
 //函数原型
 void list_cities（int number，City p []）{
 for（int i = 0; i< number; i ++）{
 cout<< p [i] .get_name（）<< endl; 
 
 
 $ / code $ / pre 
 
解决方案
阵列默认为 转换为指针，然后将其作为参考传递。因此，没有明确规定通过引用传递数组。也就是说，
 
 
  void list_cities（int number，City& p []）
  
不是 p [] 作为参考传递，但是使得 
 
 
 
代码：
 
 （int i = 0; i< number; i ++）
 {
 cout< < p [I] .get_name（）<< ENDL; 
 
 
 
 int main（）
 {
 City * p = new City [number]; 
 list_cities（number，p）; 
 delete [] p; 
} 
  
 
I am in the process of learning c++. So i know a method by which you send something to function and then work as if it was call by value but actually it is call by reference. For example  
void myFUNC(string& x)
Now, I have a dynamically created array of objects. I want to pass the array to function like a method above. Here's the code snippets  
City *p = new City[number]; // pointer to dynamic array of class objects

//function prototype
void list_cities(int number, City p[]){
    for(int i=0; i<number; i++){
        cout<<p[i].get_name()<<endl;
    }
}

解决方案
Arrays are by default converted to pointers, which are then passed as reference. So, there is no provision for explicitly passing arrays by reference. That is,
void list_cities(int number, City &p[])
is not p[] being passed as reference, but makes p[] an array of references.

Code:
void list_cities(int number, City p[])
{
    for(int i=0; i<number; i++)
    {
        cout<<p[i].get_name()<<endl;
    }
}

int main()
{
    City *p = new City[number];
    list_cities(number,p);
    delete[] p;
}


                        
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