XSLT 多重替换 [英] XSLT multiple replacing

问题描述

我有一个 XML 文档，类似于

I have an XML document, something like

<root>
  <item>_x0034_SOME TEXT</item>
  <item>SOME_x0020_TEXT</item>
  <item>SOME_x0020_TEXT_x0032_</item>
</root>

我将其导出为 HTML，但在替换转义字符时遇到问题.我在网上找到了几个模板来进行文本替换，但它们都与此类似:

I'm exporting it to HTML, but I have problems replacing escape characters. I have found several templates in the web to do text replacing but they all are similar to this:

<xsl:template name="replaceString">
    <xsl:param name="strOrig"/>
    <xsl:param name="strSearch"/>
    <xsl:param name="strReplace"/>
    <xsl:choose>
        <xsl:when test="contains($strOrig, $strSearch)">
            <xsl:value-of select="substring-before($strOrig, $strSearch)"/>
            <xsl:value-of select="$strReplace"/>
            <xsl:call-template name="replaceString">
                <xsl:with-param name="strOrig" select="substring-after($strOrig, $strSearch)"/>
                <xsl:with-param name="strSearch" select="$strSearch"/>
                <xsl:with-param name="strReplace" select="$strReplace"/>
            </xsl:call-template>
        </xsl:when>
        <xsl:otherwise>
            <xsl:value-of select="$strOrig"/>
        </xsl:otherwise>
    </xsl:choose>
</xsl:template>

我不确定如何使用它来进行多次替换.我试过这个:

I'm not sure how I can use this to do the multiple replacements. I have tried this:

<xsl:for-each select="PinnacleSys.PMC.Plugins.PVR.PvrChannelDescriptorWrapper/PinnacleSys.PMC.Plugins.PVR.DVBTPvrChannelDescriptor">

    <!--name="<xsl:value-of select="replace(replace(Name, '_x0020_', ' '), '_x0034_', '3')"/>" -->
    <!--name="<xsl:value-of select="Name"/>"-->
    <xsl:variable name="var1" select="Text" />
        <xsl:value-of select="replace($FeatureInfo,'Feature=','TESTING')"/>

    name="
        <xsl:call-template name="replaceString">
            <xsl:with-param name="strOrig" select="Name"/>
            <xsl:with-param name="strSearch" select="'_x0020_'"/>
            <xsl:with-param name="strReplace" select="' '"/>
        </xsl:call-template>
        <xsl:call-template name="replaceString">
            <xsl:with-param name="strOrig" select="Name"/>
            <xsl:with-param name="strSearch" select="'_x0030_'"/>
            <xsl:with-param name="strReplace" select="'0'"/>
        </xsl:call-template>
       ..."

但这只是将字符串连接了几次，每次都有不同的替换.我还研究了变量；如果我可以将模板调用的结果分配给一个变量，我可以获得一个脏但有效的解决方案，这对我来说已经足够了.但是我没能，也不知道是否有可能.

But this just concatenates the string several times, each with a different replacement. I have also investigated variables; if I could assign the result of a template call to a variable, I could get a dirty-but-works solution, which is enough for me. However I haven't been able and don't know if it's possible.

最好的方法是什么?

我只能使用 1.0 XSLT(使用 2.0 我可以在另一个内部调用一个 replace()).

I'm restricted to 1.0 XSLT (with 2.0 I could call one replace() inside another).

推荐答案

对于使用模板进行替换的本机 XSLT 1.0 解决方案，需要嵌套各个替换，如下所示.由于潜在的替换次数，这显然效率不高.优化后的版本如下.

For a native XSLT 1.0 solution using a template for replacement, the individual replacements need to be nested, as shown here. This obviously isn't efficient due to the potential number of replacements. An optimized version is given below.

<xsl:template match="item">
<xsl:copy>
    <xsl:call-template name="replace-substring">
        <xsl:with-param name="original">
            <xsl:call-template name="replace-substring">
                <xsl:with-param name="original">
                    <xsl:call-template name="replace-substring">
                        <xsl:with-param name="original" select="."/>
                        <xsl:with-param name="substring" select="'_x0020_'"/>
                        <xsl:with-param name="replacement" select="' '"/>
                    </xsl:call-template>
                </xsl:with-param>
                <xsl:with-param name="substring" select="'_x0032_'"/>
                <xsl:with-param name="replacement" select="'2'"/>
            </xsl:call-template>
        </xsl:with-param>
        <xsl:with-param name="substring" select="'_x0034_'"/>
        <xsl:with-param name="replacement" select="'4'"/>
    </xsl:call-template>
</xsl:copy>
</xsl:template>

<xsl:template name="replace-substring">
<xsl:param name="original"/>
<xsl:param name="substring"/>
<xsl:param name="replacement" select="''"/>
<xsl:choose>
    <xsl:when test="contains($original, $substring)">
        <xsl:value-of select="substring-before($original, $substring)"/>
        <xsl:copy-of select="$replacement"/>
        <xsl:call-template name="replace-substring">
            <xsl:with-param name="original" select="substring-after($original, $substring)"/>
            <xsl:with-param name="substring" select="$substring"/>
            <xsl:with-param name="replacement" select="$replacement"/>
        </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
        <xsl:value-of select="$original"/>
    </xsl:otherwise>
</xsl:choose>
</xsl:template>

由于输出是 HTML(XML 也可以)，_xNNNN_ 字符串可以转换为其十六进制数字字符引用，例如 &#xNNNN;.这个模板很有效.

Since the output is HTML (XML would be fine too), the _xNNNN_ strings can be converted to their hex numeric character references, e.g., &#xNNNN;. This template is efficient.

<xsl:template match="item">
<xsl:copy>
    <xsl:call-template name="replaceChars">
        <xsl:with-param name="original" select="."/>
    </xsl:call-template>
</xsl:copy>
</xsl:template>

<xsl:template name="replaceChars">
<xsl:param name="original"/>
<xsl:choose>
    <xsl:when test="contains($original, '_x')">
        <xsl:value-of select="substring-before($original, '_x')"/>
        <xsl:variable name="after" select="substring-after($original, '_x')"/>
        <xsl:variable name="char" select="substring-before($after, '_')"/>
        <xsl:value-of select="concat('&amp;#x',$char,';')" disable-output-escaping="yes"/>
        <xsl:call-template name="replaceChars">
            <xsl:with-param name="original" select="substring-after($after, '_')"/>
        </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
        <xsl:value-of select="$original"/>
    </xsl:otherwise>
</xsl:choose>
</xsl:template>

这是结果输出.

<root>
    <item>&#x0034;SOME TEXT</item>
    <item>SOME&#x0020;TEXT</item>
    <item>SOME&#x0020;TEXT&#x0032;</item>
</root>

这篇关于XSLT 多重替换的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！