XSLT 字符串替换 [英] XSLT string replace
问题描述
我不太了解 XSL,但我需要修复此代码,我已将其简化以使其更简单.
我收到此错误
I don't really know XSL but I need to fix this code, I have reduced it to make it simpler.
I am getting this error
无效的 XSLT/XPath 函数
Invalid XSLT/XPath function
在这条线上
<xsl:variable name="text" select="replace($text,'a','b')"/>
这是 XSL
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:inm="http://www.inmagic.com/webpublisher/query" version="1.0">
<xsl:output method="text" encoding="UTF-8" />
<xsl:preserve-space elements="*" />
<xsl:template match="text()" />
<xsl:template match="mos">
<xsl:apply-templates />
<xsl:for-each select="mosObj">
'Notes or subject'
<xsl:call-template
name="rem-html">
<xsl:with-param name="text" select="SBS_ABSTRACT" />
</xsl:call-template>
</xsl:for-each>
</xsl:template>
<xsl:template name="rem-html">
<xsl:param name="text" />
<xsl:variable name="text" select="replace($text, 'a', 'b')" />
</xsl:template>
</xsl:stylesheet>
谁能告诉我它有什么问题?
Can anyone tell me what's wrong with it?
推荐答案
replace
不适用于 XSLT 1.0.
replace
isn't available for XSLT 1.0.
Codesling 有一个字符串替换模板,你可以用作函数的替代:
Codesling has a template for string-replace you can use as a substitute for the function:
<xsl:template name="string-replace-all">
<xsl:param name="text" />
<xsl:param name="replace" />
<xsl:param name="by" />
<xsl:choose>
<xsl:when test="$text = '' or $replace = ''or not($replace)" >
<!-- Prevent this routine from hanging -->
<xsl:value-of select="$text" />
</xsl:when>
<xsl:when test="contains($text, $replace)">
<xsl:value-of select="substring-before($text,$replace)" />
<xsl:value-of select="$by" />
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="substring-after($text,$replace)" />
<xsl:with-param name="replace" select="$replace" />
<xsl:with-param name="by" select="$by" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$text" />
</xsl:otherwise>
</xsl:choose>
</xsl:template>
调用方式:
<xsl:variable name="newtext">
<xsl:call-template name="string-replace-all">
<xsl:with-param name="text" select="$text" />
<xsl:with-param name="replace" select="a" />
<xsl:with-param name="by" select="b" />
</xsl:call-template>
</xsl:variable>
另一方面,如果您实际上只需要用另一个字符替换一个字符,您可以调用 translate
具有类似的签名.像这样的东西应该可以正常工作:
On the other hand, if you literally only need to replace one character with another, you can call translate
which has a similar signature. Something like this should work fine:
<xsl:variable name="newtext" select="translate($text,'a','b')"/>
另外,注意,在这个例子中,我将变量名改为newtext",在XSLT中变量是不可变的,所以你不能像你一样做$foo = $foo
的等价物在您的原始代码中.
Also, note, in this example, I changed the variable name to "newtext", in XSLT variables are immutable, so you can't do the equivalent of $foo = $foo
like you had in your original code.
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