XSLT 1.0:替换节点集中所有出现的字符串 [英] XSLT 1.0: Replacing all occurences of a string in a node-set

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问题描述

我有以下函数将字符串 ($text) 中所有出现的搜索字符串 ($replace) 替换为另一个字符串 ($by):

I have the following function which replaces all occurences of a search-string ($replace) in a string ($text) with another string ($by):

<xsl:template name="string-replace-all">
  <xsl:param name="text" />
  <xsl:param name="replace" />
  <xsl:param name="by" />
  <xsl:choose>
    <xsl:when test="contains($text, $replace)">
      <xsl:value-of select="substring-before($text,$replace)" />
      <xsl:value-of select="$by" />
      <xsl:call-template name="string-replace-all">
        <xsl:with-param name="text"
        select="substring-after($text,$replace)" />
        <xsl:with-param name="replace" select="$replace" />
        <xsl:with-param name="by" select="$by" />
      </xsl:call-template>
    </xsl:when>
    <xsl:otherwise>
      <xsl:value-of select="$text" />
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>

这适用于替换单个字符串中的文本,但在尝试替换节点集中的文本时不起作用.

This works fine for replacing text in individual strings, however it doesn't work when trying to replace text in a node-set.

我正在寻找的是一个函数,例如,它采用以下 XML 文档:

What I am looking for is a function which takes, for example, the following XML document:

<nodeSet> 
  <node>a1;a2;a3</node> 
  <node>b1;b2;b3</node>
</nodeSet>

并输出以下内容:

<nodeSet> 
  <node>a1#a2#a3</node> 
  <node>b1#b2#b3</node>
</nodeSet>  

当预先知道目标字符串和替换字符串时,以下模板会起作用:

The following template does the job when the target and replacement strings are known in advance:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:exsl="http://exslt.org/common"
extension-element-prefixes="exsl"
>

  <xsl:template name="string-replace-all-in-nodeset">
    <xsl:param name="nodeset" />
    <xsl:apply-templates select="exsl:node-set($nodeset)" mode="str-repl-in-nodeset"/>
  </xsl:template>

  <xsl:template match="*/text()" mode="str-repl-in-nodeset">
    <xsl:call-template name="string-replace-all">
      <xsl:with-param name="text" select="."/>
      <xsl:with-param name="replace" select=" ';' "/>
      <xsl:with-param name="by" select=" '#' "/>
    </xsl:call-template>
  </xsl:template>


  <xsl:template name="string-replace-all">
    <xsl:param name="text" />
    <xsl:param name="replace" />
    <xsl:param name="by" />
    <xsl:choose>
      <xsl:when test="contains($text, $replace)">
        <xsl:value-of select="substring-before($text,$replace)" />
        <xsl:value-of select="$by" />
        <xsl:call-template name="string-replace-all">
          <xsl:with-param name="text" select="substring-after($text,$replace)" />
          <xsl:with-param name="replace" select="$replace" />
          <xsl:with-param name="by" select="$by" />
        </xsl:call-template>
      </xsl:when>
      <xsl:otherwise>
        <xsl:value-of select="$text" />
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>

  <xsl:template match="@*|node()" mode="str-repl-in-nodeset">
    <xsl:copy>
      <xsl:apply-templates select="@*|node()" mode="str-repl-in-nodeset"/>
    </xsl:copy>
  </xsl:template>

</xsl:stylesheet>

但是,我需要能够动态传递目标和替换字符串(在本例中为;"和#").有没有办法将这些参数传递给匹配所有文本节点的模板(match="*/text()")或任何其他方式来实现我想要的?

However, I need to be able to pass the target and replacement string (';' and '#' in this case) dynamically. Is there any way of passing these parameters to the template matching all text nodes (match="*/text()") or any other way of achieving what I want?

推荐答案

这里是一个样式表,它定义了 replaceby 字符串的全局参数,然后将它们传递给到该模式下的所有模板 str-repl-in-nodeset:

Here is a stylesheet that defines global parameters for the replace and by strings and then passes them on to all templates in that mode str-repl-in-nodeset:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    version="1.0"
    xmlns:exsl="http://exslt.org/common"
    exclude-result-prefixes="exsl">

    <xsl:param name="ns1">
        <nodeSet> 
            <node>a1;a2;a3</node> 
            <node>b1;b2;b3</node>
        </nodeSet>
    </xsl:param>

    <xsl:param name="replace" select="';'"/>
    <xsl:param name="by" select="'#'"/>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="/">
        <xsl:apply-templates select="exsl:node-set($ns1)" mode="str-repl-in-nodeset">
            <xsl:with-param name="replace" select="$replace"/>
            <xsl:with-param name="by" select="$by"/>
        </xsl:apply-templates>
    </xsl:template>

    <xsl:template match="/ | @* | node()" mode="str-repl-in-nodeset">
        <xsl:param name="replace"/>
        <xsl:param name="by"/>
        <xsl:copy>
            <xsl:apply-templates select="@*|node()" mode="str-repl-in-nodeset">
                <xsl:with-param name="replace" select="$replace"/>
                <xsl:with-param name="by" select="$by"/>
            </xsl:apply-templates>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="*/text()" mode="str-repl-in-nodeset">
        <xsl:param name="replace"/>
        <xsl:param name="by"/>
        <xsl:call-template name="string-replace-all">
            <xsl:with-param name="text" select="."/>
            <xsl:with-param name="replace" select="$replace"/>
            <xsl:with-param name="by" select="$by"/>
        </xsl:call-template>
    </xsl:template>


    <xsl:template name="string-replace-all">
        <xsl:param name="text" />
        <xsl:param name="replace" />
        <xsl:param name="by" />
        <xsl:choose>
            <xsl:when test="contains($text, $replace)">
                <xsl:value-of select="substring-before($text,$replace)" />
                <xsl:value-of select="$by" />
                <xsl:call-template name="string-replace-all">
                    <xsl:with-param name="text" select="substring-after($text,$replace)" />
                    <xsl:with-param name="replace" select="$replace" />
                    <xsl:with-param name="by" select="$by" />
                </xsl:call-template>
            </xsl:when>
            <xsl:otherwise>
                <xsl:value-of select="$text" />
            </xsl:otherwise>
        </xsl:choose>
    </xsl:template>


</xsl:transform>

这篇关于XSLT 1.0:替换节点集中所有出现的字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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