XSLT if - 属性等于字符串 [英] XSLT if - attribute equals string

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问题描述

我正在使用 xsl:if 在较大的 xsl:template 块中执行一个小条件,我想测试一个属性的相等性当前 xsl:template 匹配的节点.

I'm using a xsl:if to perform a small condition in a larger xsl:template block, and I'd like to test equality of an attribute of the current xsl:template matched node.

以下不起作用:

<xsl:template match="sometag[@type='sometype']">
    ==Sometag==
    <xsl:if test="@something!='hidden'">something</xsl:if>
    <!--a lot of other stuff that I don't want to duplicate by multiplying the xsl:templates-->
<xsl:template>

这个测试似乎总是评估为假,也许我没有好的语法?

This test seems to be always evaluating to false, maybe I don't have the good syntax?

这个 XML:

<sometag type="sometype" something="visible"/>
<sometag type="sometype" something="hidden"/>
<sometag type="sometype"/>

应该给

==Sometag==
something...
==Sometag==
==Sometag==
something...

推荐答案

第二个标签不应打印某物"部分.

the 2nd tag should not get the "something" part printed.

我不完全确定您要实现的目标,但我会尝试一下.

I am not entirely sure what you are trying to achieve, but I'll give it a try.

您的一个 sometag 元素根本没有 something 属性.没有这个属性与 @something!='hidden' 完全不同.因此,如果 something 属性不存在,则不会输出字符串something".

One of your sometag elements does not have a something attribute at all. Not having this attribute is entirely different from @something!='hidden'. So, the string "something" is not output if the something attribute is not present.

因此,您需要在评估 xsl:if 条件之前测试是否存在 something 属性.

Because of this you need to test whether there is a something attribute before your xsl:if condition is evaluated.

输入

<?xml version="1.0" encoding="utf-8"?>
<root>
<sometag type="sometype" something="visible"/>
<sometag type="sometype" something="hidden"/>
<sometag type="sometype"/>
</root>

样式表

<?xml version="1.0" encoding="utf-8"?>

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

   <xsl:output method="text"/>
   <xsl:strip-space elements="*"/>

   <xsl:template match="/root">
      <xsl:apply-templates/>
   </xsl:template>

   <xsl:template match="sometag[@type='sometype']">
      <xsl:text>==Sometag==</xsl:text>
      <xsl:choose>
         <xsl:when test="@something">
            <xsl:if test="@something!='hidden'">
               <xsl:text>something</xsl:text>
            </xsl:if>
         </xsl:when>
         <xsl:otherwise>
            <xsl:text>something</xsl:text>
         </xsl:otherwise>
      </xsl:choose>
   </xsl:template>

</xsl:stylesheet>

编辑 @Tim C 建议了一个更短的版本:

EDIT @Tim C has suggested an even shorter version:

 <xsl:template match="sometag[@type='sometype']">
    <xsl:text>==Sometag==</xsl:text>
    <xsl:if test="@something!='hidden' or not(@something)">
       <xsl:text>something</xsl:text>
    </xsl:if>
 </xsl:template>

输出

==Sometag==something==Sometag====Sometag==something

这篇关于XSLT if - 属性等于字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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