使用sed在xml文件中查找和替换 [英] Find and replace in xml file using sed

问题描述

我需要查找并替换特定 xml 元素的值.条件如下:

I need to find and replace the value of the specific xml element. The conditions are as follows:

• 元素enabled的值必须从0改为1；
• enabled 必须是 somenode 元素的子元素

• the value of element enabled must be changed from 0 to 1;
• enabled must be the child of an somenode element

我的测试 xml 如下所示:

My test xml looks like this:

<somenode name="node1">
    <some></some>
    <enabled>0</enabled>
    <some></some>
</somenode>

<someothernode name="node2">
    <some></some>
    <enabled>0</enabled>
    <some></some>
</someothernode>

<somenode name="node3">
    <some></some>
    <enabled>0</enabled>
    <some></some>
</somenode>

我希望第一个和第三个 enabled 元素会改变.到目前为止，我已经设法编写了这个 sed 命令:

I expect that first and third enabled elements would be changed. So far I have managed to write this sed command:

sed -n "1h;1!H;${;g;s|\(<somenode [^>]*>\)\(.*\)\(<enabled>\s*\)0\(\s*</enabled>\)\(.*</somenode>\)|\1\2\3 1 \4\5|g;p;}" test.xml

但它只改变了最后一个，我相信这是由于贪婪匹配.任何帮助将不胜感激.

but it changes only the last one, and I believe it is due to greedy match. Any help would be appreciated.

推荐答案

尽可能使用 xmlstarlet:

Use xmlstarlet if possible:

echo '
<root>
<somenode name="node1">
   <some></some>
   <enabled>0</enabled>
   <some></some>
</somenode>

<someothernode name="node2">
   <some></some>
   <enabled>0</enabled>
   <some></some>
</someothernode>

<somenode name="node3">
   <some></some>
   <enabled>0</enabled>
   <some></some>
</somenode>
</root>
' > testfile.xml


xml val testfile.xml
xml el -v testfile.xml

xml ed --help

# version 1
xml ed -u "//somenode[1]/enabled" -v '1' \
       -u "//somenode[2]/enabled" -v '1' \
       testfile.xml  

# version 2  (-L for in-place editing; xmlstarlet v1.0.2)
xml ed -L -u "//somenode[@name='node1']/enabled" -v '1' \
          -u "//somenode[@name='node3']/enabled" -v '1' \
          testfile.xml  

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