替换 R 中的值 - 收到错误 [英] Replacing Values in R - Error Received

问题描述

所以我有一个填充核苷酸信息的数据框(称为 gen):每个值是 A、C、G 或 T.我希望用 1 替换 A，用 2 替换 C，用 3 替换 G，和 T与 4. 当我使用函数 gen[gen==A] = 1 时，出现错误:

So I have a data frame (called gen) filled with nucleotide information: each value is either A, C, G, or T. I am looking to replace A with 1, C with 2, G with 3, and T with 4. When I use the function gen[gen==A] = 1, I get the error:

[<-.data.frame(*tmp*, gen == A, value = 1) 中的错误:未找到对象A"

Error in [<-.data.frame(*tmp*, gen == A, value = 1) : object 'A' not found

我什至尝试使用 gen <- replace(gen, gen == A, 1)，但它给了我同样的错误.有谁知道如何解决这个错误?如果没有，是否可以在 R 中安装一个程序包，该程序包可以将 A、C、G 和 T 转换为数值?

I even tried using gen <- replace(gen, gen == A, 1), but it gives me the same error. Does anyone know how to fix this error? If not, is there a package that I can install in R with a program that will convert A, C, G, and T to numeric values?

谢谢

推荐答案

您需要将 A 用引号括起来，否则 R 会查找名为 A 的变量.如果列是字符向量:

You need to wrap A in quotes or else R looks for a variable named A. If the columns are character vectors:

R> gen = data.frame(x = sample(c("A", "C", "G", "T"), 10, replace = TRUE), y = sample(c("A", "C", "G", "T"), 10, replace=  TRUE), stringsAsFactors = FALSE)
R> gen[gen == "A"] = 1
R> gen
   x y
1  1 1
2  C C
3  G T
4  T T
5  G G
6  G G
7  1 1
8  C C
9  T 1
10 1 1

也是一种一次性完成的方法

also 1 way to do all at once

R> library(car)
R> sapply(gen, recode, recodes = "'A'=1; 'C'=2; 'G'=3; 'T'=4")
      x y
 [1,] 1 1
 [2,] 2 2
 [3,] 3 4
 [4,] 4 4
 [5,] 3 3
 [6,] 3 3
 [7,] 1 1
 [8,] 2 2
 [9,] 4 1
[10,] 1 1

如果列是因子

R> gen = data.frame(x = sample(c("A", "C", "G", "T"), 10, replace = TRUE), y = sample(c("A", "C", "G", "T"), 10, replace=  TRUE))
R> sapply(gen, as.numeric)
      x y
 [1,] 1 1
 [2,] 2 4
 [3,] 1 2
 [4,] 4 1
 [5,] 2 2
 [6,] 1 4
 [7,] 4 3
 [8,] 3 3
 [9,] 2 4
[10,] 4 2

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