发现周边元件和元件阵列中的 [英] find elements surrounding and element in an array

问题描述

我有一个多维数组，我希望得到周围的数组中的特定元素的元素。例如，如果我有以下几点：

  [1,2,3,4,5,6]
 [8,9,7,5,2,6]
 [1,6,8,7,5,8]
 [2,7,9,5,4,3]
 [9,6,7,5,2,1]
 [4,7,5,2,1,3]
 

我如何找到各地的任何上述要素的8个元素。和我怎么照顾元素的边缘。

我想通了就是，写一个9号线code这一点，这是很明显的一种方式，有没有更好的解决办法？
谢谢

解决方案

 为（i = 0; I＆LT; array.length，我++）{
            为（J = 0; J＆LT;阵[I]。长度; J ++）{
                为（X = Math.max（0，I  -  1）; X＆下; = Math.min第（i + 1，array.length）; X ++）{
                    对于（Y = Math.max（0，J  -  1）; Y＆LT; = Math.min（J + 1，
                            数组[I]。长度）; Ÿ++）{
                        如果（X GT; = 0＆放大器;＆放大器y与其所连接; = 0＆放大器;＆放大器; X＆下; array.length
                                ＆功放;＆安培; Y'LT;数组[我]。长度）{
                            如果（X！= ||我Y！= j）条{
                            System.out.print（数组[X] [Y] +）;
                            }
                        }
                    }
                }
                的System.out.println（\\ n）;
            }
        }
 

感谢所有谁回答的人，但我理解了它与，我发现这个职位刚才，尤其是解决方案。再次感谢：）

I have a multidimensional array, I want to get the elements surrounding a particular element in that array. For example if I have the following:

[[1,2,3,4,5,6]
 [8,9,7,5,2,6]
 [1,6,8,7,5,8]
 [2,7,9,5,4,3]
 [9,6,7,5,2,1]
 [4,7,5,2,1,3]]

How do I find all the 8 elements around any of the above elements. and how do I take care of elements at the edges.

One way I figured out is, to write a 9 line code for this , which is obvious, is there a better solution? thanks

解决方案

for (i = 0; i < array.length; i++) {
            for (j = 0; j < array[i].length; j++) {
                for (x = Math.max(0, i - 1); x <= Math.min(i + 1, array.length); x++) {
                    for (y = Math.max(0, j - 1); y <= Math.min(j + 1,
                            array[i].length); y++) {
                        if (x >= 0 && y >= 0 && x < array.length
                                && y < array[i].length) {
                            if(x!=i || y!=j){
                            System.out.print(array[x][y] + " ");
                            }
                        }
                    }
                }
                System.out.println("\n");
            }
        }

Thanks to all the people who have answered, but i figured it out with the help of this post which i found just now, and above is the solution. thanks again :)

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