创建具有不同类型的元件的阵列 [英] Create an array with elements of different types

问题描述

我要声明，包含不同的变量类型的数组，主要是：

I need to declare an array that consists of different variable types, mainly:

char *A; uint32_t B; int C;

我在教程了解，在数组中声明的类型和元素的数量。这么说来是这样的：

As I understood in the tutorials, in the array you declare the type and the number of element. So to say something like:

int a[3];

，其中在这种情况下，三个元件的类型都是整数。
那么，如何做我想要声明的是由上面提到的三种不同类型的数组？

where in this case, the type of the three elements are all integers. So how do I want to declare an array that consists of the three different types mentioned above?

推荐答案

用C数组的定义是相同类型的元素的集合。可能是你正在寻找一个结构。

The definition of an array in C is a collection of elements of the SAME type. What you are looking for is probably a struct.

struct s
{
    char* A;
    uint32_t B;
    int C;
};

int main(void)
{
    struct s test;
    test.A = "Hello";
    test.B = 12345;
    test.C = -2;

    // Do stuff with 'test'
    return 0;
}

或者，如下面的评论中提到，你可以使用联盟来代替。但你不能使用A，B和C，同时像我在上面的例子 - 只是其中之一将被存储 - 在我的例子这将是C

Or, as mentioned in a comment below, you could use a union instead. But then you can't use A, B, and C at the same time like I have in the example above - only one of them will be stored - in my example it would be C.

如果你需要，可以使结构数组。

You can make an array of structures if you need to.

struct s test[5];  // Array of structures

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