在Python 2 numpy的阵列交错排 [英] Interleave rows of two numpy arrays in Python

问题描述

我想交织相同大小的两个numpy的阵列的行。
我想出了这个解决方案。

I wanted to interleave the rows of two numpy arrays of the same size. I came up with this solution.

# A and B are same-shaped arrays
A = numpy.ones((4,3))
B = numpy.zeros_like(A)
C = numpy.array(zip(A[::1], B[::1])).reshape(A.shape[0]*2, A.shape[1])
print C

输出

[[ 1.  1.  1.]
 [ 0.  0.  0.]
 [ 1.  1.  1.]
 [ 0.  0.  0.]
 [ 1.  1.  1.]
 [ 0.  0.  0.]
 [ 1.  1.  1.]
 [ 0.  0.  0.]]

有一个更清洁，更快，更好，numpy的，唯一的办法？

Is there a cleaner, faster, better, numpy-only way?

推荐答案

这也许是更清楚一点做的：

It is maybe a bit clearer to do:

A = np.ones((4,3))
B = np.zeros_like(A)

C = np.empty((A.shape[0]+B.shape[0],A.shape[1]))

C[::2,:] = A
C[1::2,:] = B

和它可能是一个快一点为好，我猜。

and it's probably a bit faster as well, I'm guessing.

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