如何使用 RestSharp 解析 JSON? [英] How to parse JSON using RestSharp?

问题描述

var client = new RestClient("http://10.0.2.2:50670/api");

var request = new RestRequest("Inventory", Method.GET);

request.OnBeforeDeserialization = resp => { resp.ContentType = "application/json"; };

// execute the request to return a list of InventoryItem
RestResponse<JavaList<InventoryItem>> response = (RestResponse<JavaList<InventoryItem>>)client.Execute<JavaList<InventoryItem>>(request);

返回的内容是一个JSON字符串，一个对象数组.以下是它的简短摘录:

The content returned is a JSON string, an array of objects. The following is a short excerpt of it:

[{"Id":1,"Upc":"1234567890","Quantity":100,"Created":"2012-01-01T00:00:00","Category":"Tequila","TransactionType":"Audit","MetaData":"PATRON 750ML"},{"Id":2,"Upc":"2345678901","Quantity":110,"Created":"2012-01-01T00:00:00","Category":"Whiskey","TransactionType":"Audit","MetaData":"JACK DANIELS 750ML"},{"Id":3,"Upc":"3456789012","Quantity":150,"Created":"2012-01-01T00:00:00","Category":"Vodka","TransactionType":"Audit","MetaData":"ABSOLUT 750ml"}]

错误信息:

由于对象的当前状态，操作无效

Operation is not valid due to the current state of the object

这里有什么问题?我的 InventoryItem 与 JSON 字符串中的每个对象具有相同的属性.我错过了一步吗?

What is wrong here? My InventoryItem has the same properties as each object in the JSON string. Am I missing a step?

推荐答案

我怀疑 RestSharp 中使用的 SimpleJson 无法反序列化为 JavaList.

I suspect that SimpleJson, used in RestSharp can't deserialise to a JavaList.

首先我会尝试反序列化为:

First I would try deserialising to a:

List<InventoryItem>

如果失败，我推荐 ServiceStack.Text - .Net 最快的 JSON 库；并做:

Failing that, I recommend ServiceStack.Text - .Net's fastest JSON library; and do:

var response = client.Execute(request);
var thingYouWant = JsonSerializer.DeserializeFromString<List<InventoryItem>>(response.Content);

这实际上是我自己做的.

This is actually what I do myself.

编辑(感谢评论员):在较新的版本中，这将是:

Edit (Thank you to commentators): In newer versions this would now be:

var deserializer = new JsonDeserializer();
deserializer.Deserialize<List<InventoryItem>>(response);

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