在python函数中返回多个值 [英] Return more than one value in python function
问题描述
我试图在 python 中将 *args 与 for 循环一起使用,但是我没有看到如何返回传递给函数的所有值,该函数应该返回所有偶数
I was trying to use *args with a for loop in python, however I don't see how to return all the values passed to the function, which should return all the even numbers
def f_even(*args):
for item in args:
if item%2 == 0:
return item
上面的代码只返回第一个值,因为我猜在返回后它会退出函数.确实,如果我改用打印,它会起作用
The above code returns only the first value, as I guess after the return it goes out of the function. Indeed, if I use print instead, it works
当我将 (1,2,3,4,5) 传递给函数时,我试图找到一种方法来返回一个包含所有偶数的元组
I'm trying to find a way to return a tuple with all the even numbers when I pass let's say (1,2,3,4,5) to the function
谢谢!
推荐答案
在 python 中,你可以使用列表理解来做到这一点.将使您的代码更具可读性,并且也会缩小它.
In python you can use list comprehension to do this. will make you code more readable and will shrink it too.
def f_even(*args):
return [elem for elem in args if elem % 2 == 0]
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