从C ++函数返回多个值 [英] Returning multiple values from a C++ function

问题描述

是否有从C ++函数返回多个值的首选方法？例如，假设一个函数将两个整数相除，并返回商和余数。我通常看到的一种方法是使用参考参数：

Is there a preferred way to return multiple values from a C++ function? For example, imagine a function that divides two integers and returns both the quotient and the remainder. One way I commonly see is to use reference parameters:

void divide(int dividend, int divisor, int& quotient, int& remainder);

变体是返回一个值，并通过引用参数传递另一个值：

A variation is to return one value and pass the other through a reference parameter:

int divide(int dividend, int divisor, int& remainder);

另一种方法是声明一个结构来包含所有结果，并返回：

Another way would be to declare a struct to contain all of the results and return that:

struct divide_result {
    int quotient;
    int remainder;
};

divide_result divide(int dividend, int divisor);

这些方法之一通常是首选还是有其他建议？

Is one of these ways generally preferred, or are there other suggestions?

编辑：在现实世界的代码中，可能有两个以上的结果。

In the real-world code, there may be more than two results. They may also be of different types.

推荐答案

对于返回两个值，我使用 std :: pair （通常typedef'd）。你应该看看 boost :: tuple （在C ++ 11和更新版本中，有 std :: tuple ）超过两个返回结果。

For returning two values I use a std::pair (usually typedef'd). You should look at boost::tuple (in C++11 and newer, there's std::tuple) for more than two return results.

这篇关于从C ++函数返回多个值的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！