是否有反向“成员"?ruby 中的方法? [英] Is there an inverse 'member?' method in ruby?

问题描述

我经常发现自己在检查某个值是否属于某个集合.据我了解，人们通常为此使用 Enumerable#member?.

I often find myself checking if some value belongs to some set. As I understand, people normally use Enumerable#member? for this.

end_index = ['.', ','].member?(word[-1]) ? -3 : -2

然而，这感觉不如 Ruby 中的大多数东西优雅.我宁愿把这段代码写成

However, this feels a little less elegant than most of things in Ruby. I'd rather write this code as

end_index = word[-1].is_in?('.', ',') ? -3 : -2

但是我找不到这样的方法.它甚至存在吗?如果没有，对原因有什么想法吗?

but I fail to find such method. Does it even exist? If not, any ideas as to why?

推荐答案

不在 ruby​​ 中，而是 在 ActiveSupport 中:

Not in ruby but in ActiveSupport:

characters = ["Konata", "Kagami", "Tsukasa"]
"Konata".in?(characters) # => true

这篇关于是否有反向“成员"?ruby 中的方法?的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！