ruby 以四人为一组处理数组元素 [英] ruby working on array elements in groups of four

问题描述

当每个元素都需要处理时，我有一个 ruby​​ 脚本数组:

I have a ruby script array when each element needs processing :

threads = []
elemets.each do  |element|
    threads.push(Thread.new{process(element)}}
end
threads.each { |aThread|  aThread.join }

然而，由于资源限制，如果一次不再处理四个元素，脚本将以最佳方式工作.

how ever due to resource limitations, the script works in an optimal way if no more the four elements are processed at a time.

不，我知道我可以转储每个循环并使用变量来计算 4 个元素然后等待但是有没有更酷的红宝石方式来做到这一点?

no I know I can dump the each loop and use a variable to count 4 elements and then wait but is there a cooler ruby way to do it ?

推荐答案

您可以为一个数组以 4 个为一组进行枚举:

You can enumerate in groups of 4 for an array:

>> [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12].each_slice(4) {|a| p a}
[1, 2, 3, 4]
[5, 6, 7, 8]
[9, 10, 11, 12]

所以你可以尝试类似的东西

So you can try something like

elements.each_slice(4) do | batch |
    batch.each do | element |
        threads.push(Thread.new{process(element)}}

    end
    (do stuff to check to see if the threads are done, otherwise wait )
end

不过，这可能不是您需要的 - 我从凌晨 3 点起就起床，只睡了几个小时.:/

Its may not be what you need, though - I have been up since 3 AM and I only had a couple of hours sleep. :/

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