以3个为一组打印python列表 [英] Print python list in groups of 3
问题描述
我有一个包含107个名字的列表，我想以3个左右的组形式打印出来，每个名称用一个标签分隔，每行后面有一个换行符，直到结束。我怎么能这样做？
I have a list of 107 names, I would like to print them out in groups of 3 or so, with each name separated by a tab, a newline after each line, until the end. How can I do this?
列表打印项目中的项目我每行只获得1个名字，这很好，我想，但我想在控制台中更多地适应，所以我想在列表中打印每行3个左右的名字，所以而不是：
with for item in list print item i only get 1 name per line of course, which is fine I guess but i'd like to fit more in the console at once so I'd like to print 3 or so names on each line as I go through the list, so instead of:
name1
name2
name3
name4
name5
name6
我会得到：
name1 name2 name3
name4 name5 name6
很难找到这个答案，我无法想出我需要的东西或我能理解的东西，我发现的大多数东西都只是处理 len（）或 range（）让我很困惑。有一些简单的方法可以做到这一点吗？谢谢！
It's kindof hard to search for an answer to this, i haven't been able to come up with quite what I need or that I could understand, most things I did find just deal with len() or range() and confused me. Is there some simple way to do this? Thank you!
使用@ inspectorG4dget的示例：
for i in range(0, len(listnames), 5):
print '\t\t'.join(listnames[i:i+5])
我得到以下信息： http://www.pasteall.org/pic/show.php?id=41159
如何清理干净，以便每列中的所有内容都很清晰？我想要什么才能轻松完成？
how can I get that cleaned up so everything is nicely aligned in each column? Is what I want possible to do easily?
推荐答案
1）
1)
li = ['sea','mountain','desert',
'Emma','Cathy','Kate',
'ii','uuuuuuuuuuuuuuuuuuu','aaa',
'round','flat','sharp',
'blueberry','banana','apple',
'red','purple','white',
'hen','tiger']
a,b = divmod(len(li),3)
itn = iter(li).next
print ''.join('%s\t%s\t%s\n' % (itn(),itn(),itn())
for i in xrange(a))\
+ ('%s\t%s\t\n' % (itn(),itn()) if b==2
else '%s\t\n' % itn() if b==1
else '')
结果
sea mountain desert
Emma Cathy Kate
ii uuuuuuuuuuuuuuuuuuu aaa
round flat sharp
blueberry banana apple
red purple white
hen tiger
。
并且要在宽度取决于列表中最长元素的列中对齐：
And to align in columns whose width depends on the longest element of the list:
li = ['sea','mountain','desert',
'Emma','Cathy','Kate',
'HH','VVVVVVV','AAA',
'round','flat','sharp',
'blueberry','banana','apple',
'red','purple','white',
'hen','tiger']
maxel = max(len(el) for el in li)
a,b = divmod(len(li),3)
itn = iter(li).next
form = '%%-%ds\t%%-%ds\t%%-%ds\n' % (maxel,maxel,maxel)
print ''.join(form % (itn(),itn(),itn())
for i in xrange(a))\
+ ('%%-%ds\t%%-%ds\t\n' %(maxel,maxel) % (itn(),itn()) if b==2
else '%%-%ds\t\n' % ma% itn() if b==1
else '')
结果
sea mountain desert
Emma Cathy Kate
HH VVVVVVV AAA
round flat sharp
blueberry banana apple
red purple white
hen tiger
。
要在列中对齐，每列的宽度取决于其中最长的元素：
To align in column, the width of each column depending upon the longest element in it:
li = ['sea','mountain','desert',
'Emma','Cathy','Kate',
'HH','VVVVVVV','AAA',
'round','flat','sharp',
'nut','banana','apple',
'red','purple','white',
'hen','tiger']
maxel0 = max(len(li[i]) for i in xrange(0,len(li),3))
maxel1 = max(len(li[i]) for i in xrange(1,len(li),3))
maxel2 = max(len(li[i]) for i in xrange(2,len(li),3))
a,b = divmod(len(li),3)
itn = iter(li).next
form = '%%-%ds\t%%-%ds\t%%-%ds\n' % (maxel0,maxel1,maxel2)
print ''.join(form % (itn(),itn(),itn())
for i in xrange(a))\
+ ('%%-%ds\t%%-%ds\t\n' %(maxel0,maxel1) % (itn(),itn()) if b==2
else '%%-%ds\t\n' % maxel0 % itn() if b==1
else '')
结果
sea mountain desert
Emma Cathy Kate
HH VVVVVVV AAA
round flat sharp
nut banana apple
red purple white
hen tiger
4）
我修改了算法，以便推广到任意数量的列。
想要的列数必须作为参数传递给参数 nc ：
from itertools import imap,islice
li = ['sea','mountain','desert',
'Emma','Cathy','Kate',
'HH','VVVVVVV','AAA',
'round','flat','sharp',
'nut','banana','apple',
'heeeeeeeeeeen','tiger','snake'
'red','purple','white',
'atlantic','pacific','antarctic',
'Bellini']
print 'len of li == %d\n' % len(li)
def cols_print(li,nc):
maxel = tuple(max(imap(len,islice(li,st,None,nc)))
for st in xrange(nc))
nblines,tail = divmod(len(li),nc)
stakes = (nc-1)*['%%-%ds\t'] + ['%%-%ds']
form = ''.join(stakes) % maxel
itn = iter(li).next
print '\n'.join(form % tuple(itn() for g in xrange(nc))
for i in xrange(nblines))
if tail:
print ''.join(stakes[nc-tail:]) % maxel[0:tail] % tuple(li[-tail:]) + '\n'
else:
print
for nc in xrange(3,8):
cols_print(li,nc)
print '-----------------------------------------------------------'
结果
len of li == 24
sea mountain desert
Emma Cathy Kate
HH VVVVVVV AAA
round flat sharp
nut banana apple
heeeeeeeeeeen tiger snakered
purple white atlantic
pacific antarctic Bellini
-----------------------------------------------------------
sea mountain desert Emma
Cathy Kate HH VVVVVVV
AAA round flat sharp
nut banana apple heeeeeeeeeeen
tiger snakered purple white
atlantic pacific antarctic Bellini
-----------------------------------------------------------
sea mountain desert Emma Cathy
Kate HH VVVVVVV AAA round
flat sharp nut banana apple
heeeeeeeeeeen tiger snakered purple white
atlantic pacific antarctic Bellini
-----------------------------------------------------------
sea mountain desert Emma Cathy Kate
HH VVVVVVV AAA round flat sharp
nut banana apple heeeeeeeeeeen tiger snakered
purple white atlantic pacific antarctic Bellini
-----------------------------------------------------------
sea mountain desert Emma Cathy Kate HH
VVVVVVV AAA round flat sharp nut banana
apple heeeeeeeeeeen tiger snakered purple white atlantic
pacific antarctic Bellini
-----------------------------------------------------------
。
但是我更喜欢显示列之间没有标签，但只有给定数量的字符。
在下面的代码中，我选择将列分隔2个字符：它是行中的2
But I prefer a displaying in which there are no tabs between columns, but only a given number of characters.
In the following code, I choosed to separate the columns by 2 characters: it is the 2 in the line
maxel = tuple(max(imap(len,islice(li,st,None,nc)))+2
代码
from itertools import imap,islice
li = ['sea','mountain','desert',
'Emma','Cathy','Kate',
'HH','VVVVVVV','AAA',
'round','flat','sharp',
'nut','banana','apple',
'heeeeeeeeeeen','tiger','snake'
'red','purple','white',
'atlantic','pacific','antarctic',
'Bellini']
print 'len of li == %d\n' % len(li)
def cols_print(li,nc):
maxel = tuple(max(imap(len,islice(li,st,None,nc)))+2
for st in xrange(nc))
nblines,tail = divmod(len(li),nc)
stakes = nc*['%%-%ds']
form = ''.join(stakes) % maxel
itn = iter(li).next
print '\n'.join(form % tuple(itn() for g in xrange(nc))
for i in xrange(nblines))
if tail:
print ''.join(stakes[nc-tail:]) % maxel[0:tail] % tuple(li[-tail:]) + '\n'
else:
print
for nc in xrange(3,8):
cols_print(li,nc)
print 'mwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwm'
结果
len of li == 24
sea mountain desert
Emma Cathy Kate
HH VVVVVVV AAA
round flat sharp
nut banana apple
heeeeeeeeeeen tiger snakered
purple white atlantic
pacific antarctic Bellini
mwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwm
sea mountain desert Emma
Cathy Kate HH VVVVVVV
AAA round flat sharp
nut banana apple heeeeeeeeeeen
tiger snakered purple white
atlantic pacific antarctic Bellini
mwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwm
sea mountain desert Emma Cathy
Kate HH VVVVVVV AAA round
flat sharp nut banana apple
heeeeeeeeeeen tiger snakered purple white
atlantic pacific antarctic Bellini
mwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwm
sea mountain desert Emma Cathy Kate
HH VVVVVVV AAA round flat sharp
nut banana apple heeeeeeeeeeen tiger snakered
purple white atlantic pacific antarctic Bellini
mwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwm
sea mountain desert Emma Cathy Kate HH
VVVVVVV AAA round flat sharp nut banana
apple heeeeeeeeeeen tiger snakered purple white atlantic
pacific antarctic Bellini
mwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwmwm
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