流列表成一组 [英] stream list into a set

问题描述

我希望重构一些代码中使用流的方式.第一个例子是我目前的做法.第二个例子是我试图使它看起来像什么.

I am looking to refactor how I have used a stream in some of my code. The first example is how I currently have done it. The second example is what im trying to make it look like.

Set<String> results = new HashSet<String>();

someDao.findByType(type)
            .stream()
            .forEach(t-> result.add(t.getSomeMethodValue()) );

看起来像这样吗?如果是这样，我该如何做呢?

Could it look something like this? If so how do I make it do it?

Set<String> results = someDao.findByType(type)
            .stream()
            .collect(  /*  ?? no sure what to put here  */ );

推荐答案

使用Collectors.toSet:

Set<String> results = someDao.findByType(type)
        .stream()
        .map(ClassName::getValue)
        .collect(Collectors.toSet());

这篇关于流列表成一组的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！