用cython为一组文件制作一个pyd [英] making one pyd for a set of files with cython

问题描述

我在一个包中有多个.py文件

I have multiple .py files in one package

packageA
    \__init__.py
    \mod1.py
    \mod2.py
    \mod3.py

我可以配置cython进行编译，然后将它们全部打包到一个 packageA.pyd 吗？

can I config cython to compile and then packing them all in one packageA.pyd ?

推荐答案

我个人最好将所有 .py 文件转换为 .pyx ，然后包括将它们放入Cython扩展名的主 .pyx 中：

Personally, I would better turn all the .py files into .pyx, then include them into the main .pyx of the Cython extension:

packageA.pyx ：

include "mod1.pyx" 
include "mod2.pyx" 
include "mod3.pyx" 

然后，使用 setup.py 看起来像这样：

Then, compile using a setup.py looking like:

from distutils.core import setup
from distutils.extension import Extension
from Cython.Distutils import build_ext

setup(
    cmdclass = {'build_ext': build_ext},
    ext_modules = [
        Extension("packageA", sources=["packageA.pyx"])
    ]
)                       

正在运行这将生成一个完整的 packageA.pyd 二进制文件。
当然，这将输出一个名为 packageA 的模块，我不知道这是否适合您，或者您是否真的需要在其中使用不同的模块您的包裹。
但是可能还有其他方法可以更好地满足您的问题...

Running this would generate an all in one packageA.pyd binary file. Of course, this will output a single module named packageA, and I don't know if this is acceptable for you, or if you really need distinct modules in your package. But there might be other ways that better fit your question...

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