通过一个三维阵列循环找到平均值和标准偏差 [英] Looping through a 3D array to find the mean and standard deviation

问题描述

好了，所以我有一个数组＆LT; 134x106x108>。我想要做的就是遍历这个数组，平均/标准偏差存储到另一个数组。因此，基本上会有134 LT; 106x108双打>，将在此meanArray和sdArray。

 ％dayv =＆LT; 134x106x108＆GT;
 sdArray =零（1106108）;
 meanArray =零（1106108）;
对于i = 1：尺寸（dayv，1）
    店内％意味着/标准差到一个数组
    meanArray（I，：，:) =挤压（平均（dayv（I，：，:)））;
    sdArray（I，：，:) =挤压（STD（dayv（I，：，:)））;
结束
 

解决方案

如果您希望您的每一个手段，是整个106x108矩阵的平均再一个简单的解决方案是使用，重塑您的3D矩阵为二维矩阵

  dayv2 =重塑（dayv，[134 106 * 108]）;
 

现在每个那些106x108矩阵是在新的矩阵的行向量。

然后

  meanArray =平均（dayv2,2）; ％获得平均每行
stdArray = STD（dayv2,0,2）;每行的标准％
 

Ok so I have an array <134x106x108>. What I'm trying to do is loop through this array and store the average/standard deviation into another array. So basically there will be 134 <106x108 doubles> that will be in this meanArray and sdArray.

 %dayv=<134x106x108>
 sdArray=zeros(1,106,108);
 meanArray=zeros(1,106,108);
for i=1:size(dayv,1)
    %store means/standard deviation into an array
    meanArray(i,:,:) = squeeze(mean(dayv(i,:,:)));
    sdArray(i,:,:) = squeeze(std(dayv(i,:,:)));
end

解决方案

If you want each of your means to be the average of an entire 106x108 matrix then one easy solution is to reshape your 3d matrix into a 2d matrix using,

dayv2 = reshape(dayv,[134 106*108]);

Now each of those 106x108 matrices is a row vector in your new matrix.

Then

meanArray = mean(dayv2,2); % Get mean of each row
stdArray  = std(dayv2,0,2);% Std of each row

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