Ruby/Rails 3.1:给定一个 URL 字符串，删除路径 [英] Ruby/Rails 3.1: Given a URL string, remove path

问题描述

给定任何有效的 HTTP/HTTPS 字符串，我想解析/转换它，以便最终结果正是字符串的根.

Given any valid HTTP/HTTPS string, I would like to parse/transform it such that the end result is exactly the root of the string.

给定的网址:

http://foo.example.com:8080/whatsit/foo.bar?x=y
https://example.net/

我想要结果:

http://foo.example.com:8080/
https://example.net/

我找到了文档对于 URI::Parser 不是超级平易近人.

I found the documentation for URI::Parser not super approachable.

我最初的天真解决方案是一个简单的正则表达式，例如:

My initial, naïve solution would be a simple regex like:

/\A(https?:\/\/[^\/]+\/)/

(即:匹配协议后的第一个斜杠.)

(That is: Match up to the first slash after the protocol.)

想法和想法欢迎解决.如果这是重复的，我很抱歉，但我的搜索结果不相关.

Thoughts & solutions welcome. And apologies if this is a duplicate, but my search results weren't relevant.

推荐答案

With URI::join:

require 'uri'
url = "http://foo.example.com:8080/whatsit/foo.bar?x=y"
baseurl = URI.join(url, "/").to_s
#=> "http://foo.example.com:8080/"

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