如何使用 Ruby 删除重复的 XML 节点? [英] How can I remove duplicate XML nodes using Ruby?

问题描述

假设我有这样的结构:

<one>
   <two>
     <three>3</three>
   </two>

   <two>
     <three>4</three>
   </two>

   <two>
     <three>3</three>
   </two>
</one>

有没有办法做到这一点:

Is there anyway of getting to this :

<one>
  <two>
    <three>3</three>
  </two>

  <two>
    <three>4</three>
  </two>

</one>

使用 Ruby 的库?我设法得到 this使用 Nokogiri.从我的测试来看，它似乎有效，但也许还有另一种方法，一种更好的方法.

using Ruby's libraries? I managed to get this using Nokogiri. From my tests, it appears to work, but maybe there's another approach, a better one.

推荐答案

用两行完成整个事情的一个怎么样?

How about one that does the whole thing in two lines?

seen = Hash.new(0)
node.traverse {|n| n.unlink if (seen[n.to_xml] += 1) > 1}

如果同一个节点可能出现在两个不同的父节点下，并且您不希望它们被视为重复，您可以将第二行更改为:

If there's a possibility of the same node appearing under two different parents, and you don't want those to be considered duplicates, you can change that second line to:

node.traverse {|n| n.unlink if (seen[(n.parent.path rescue "") + n.to_xml] += 1) > 1}

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