在 PowerShell 中删除重复的 XML 节点 [英] Remove Duplicate XML Nodes in PowerShell

问题描述

我有一个如下所示的 XML 文件:

I have an XML file that looks like the following:

<?xml version="1.0" encoding="UTF-8"?>
<catalog>
  <software>
    <name>MozillaFirefox</name>
    <version>31.3.0</version>
    <installer_location>/Mozilla/Firefox/31.3.0.exe</installer_location
  </software>
  <software>
    <name>GoogleChrome</name>
    <version>35.7</version>
    <installer_location>/Google/Chrome/35.7.msi</installer_location
  </software>
  <software>
    <name>MozillaFirefox</name>
    <version>33.4.0</version>
    <installer_location>/Mozilla/Firefox/33.4.0.exe</installer_location>
    </software>
</catalog>

这是我当前的代码:

#Load XML file into $catalogXML
[xml]$catalogXML = (Get-Content (C:\test.xml))

$softwareVersionsArray = $catalogXML.catalog.software

输出:

name             version      installer_location
----             -------      ------------------ 
MozillaFirefox   31.3.0       /Mozilla/Firefox/31.3.0.exe
GoogleChrome     35.7         /Google/Chrome/35.7.msi
MozillaFirefox   33.4.0       /Mozilla/Firefox/33.4.0.exe

我需要帮助进行编码，以便删除任何重复项，并保留第一个条目(即显示 Firefox 31.3.0 并删除 Firefox 33.3.4).我尝试了各种 XPath 语句和 Select -Unique 过滤器都无济于事.在此先感谢您的帮助！

I need assistance coding this so that any duplicates are removed and that the first entry is the one that is kept (i.e. Firefox 31.3.0 is displayed and Firefox 33.3.4 is removed). I've tried various XPath statements and Select -Unique filters to no avail. Thanks in advance for any help!

推荐答案

为了得到想要的结果，你可以通过 name 对元素进行分组:Group-Object name;然后从每个组中选择第一个元素:ForEach-Object {$_.Group[0]}.

To get desired results, you can group elements by name: Group-Object name; and than select first element from each group: ForEach-Object {$_.Group[0]}.

$catalogXML.catalog.software|
Group-Object name|
ForEach-Object {$_.Group[0]}

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