该声明在头文件中返回一个二维数组的函数？ [英] Declaring a function that return a 2D array in a header file?

问题描述

我想声明，我的头文件中，返回一个二维数组的功能。这怎么可能完成，因为我们已经知道了数组的大小？下面是目前我在做什么。

 类样品
{
上市：
    CHAR [X] [Y] getArr（）;
    无效等等（INT X，int y）对;
私人的：
    量静态INT X = 8;
    常量静态INT Y = 2;
    ARR的char [X] [Y]
};
 

解决方案

原来出我原来的答复是完全不正确的，但<一href=\"http://meta.stackexchange.com/questions/14932/allow-author-of-accepted-answer-to-delete-it-in-certain-circumstances\">I因为它被接受无法将其删除。从<一个href=\"http://stackoverflow.com/questions/4636144/declaring-a-function-that-return-a-2d-array-in-a-header-file/4636331#4636331\">two单独的<一个href=\"http://stackoverflow.com/questions/4636144/declaring-a-function-that-return-a-2d-array-in-a-header-file/4636361#4636361\">answers下面，我就能够编译如下：

 类样品
{
    量静态INT X = 8;
    常量静态INT Y = 2;
上市：
    焦炭的typedef SampleArray [X] [Y]    SampleArray＆安培; getArr（）;
    无效等等（INT X，int y）对;私人的：
    SampleArray ARR;
};样品:: SampleArray＆安培;样品:: getArr（）
{
    返回ARR;
}
 

（我已整理我原来的解决方案只与OP的给定类的声明，而不是 getArr的定义（））

就返回一个指针的指针。

 的char ** getArr（）;
 

I am trying to declare, within my header file, a function that returns a 2D array. How can this be accomplished, given that we already know the size of the array? Below is what I'm currently doing.

class Sample
{
public:
    char[x][y] getArr();
    void blah(int x, int y);
private:
    const static int x = 8;
    const static int y = 2;
    char arr[x][y];
};

解决方案

It turns-out my original answer was totally incorrect, but I can't delete it since it's been accepted. From two separate answers below, I was able to compile this:

class Sample
{
    const static int x = 8;
    const static int y = 2;
public:
    typedef char SampleArray[x][y];

    SampleArray& getArr();
    void blah(int x, int y);

private:
    SampleArray arr;
};

Sample::SampleArray& Sample::getArr ()
{
    return arr;
}

(I had compiled my original solution only with the OP's given class declaration, not the definition of getArr().)

Just return a pointer to a pointer.

char** getArr();

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