在操作shell脚本数组（通过PHP-CLI印） [英] Manipulating an array (printed by php-cli) in shell script

问题描述

我与shell脚本一个新手，我今天学到了很多东西。
这是一个扩展这个问题<一href=\"http://stackoverflow.com/questions/4376695/assigning-values-printed-by-php-cli-to-shell-variables\">Assigning通过PHP CLI印制值shell变量

我得到了解决阅读我的shell脚本的变量。现在，如何操纵一个数组？如果我prepare数组在我的PHP code和打印，并在我的壳回声，它显示阵列。如何访问在shell脚本数组？我试着在<特定解决方案href=\"http://stackoverflow.com/questions/2352530/how-to-manipulate-array-in-shell-script/2353298#2353298\">how操纵在shell脚本数组

用下面的code： - 结果
的 PHP code 的

  $ neededConstants =阵列（BASE_PATH，DB_HOST，DB_NAME，DB_USER，DB_PASS）;$ associativeArray =阵列（）;
的foreach（$ neededConstants每个$）
{
    $ associativeArray [$每个] =常数（$个）;
}打印$ associativeArray;
 

的壳牌code 的

 函数getConfigVals（）
{
    PHP的$ PWD'/ developer.php
}
CD ..
PROJECT_ROOT = $ PWD
CD开发商＃func1的参数：A B
结果= $（getConfigVals）为（（CNT = 0; CNT＆下; $ {＃结果}; CNT ++））
做
    回声$ {结果[$ CNT]} - $ CNT
DONE
 

我得到这样的输出： -

 阵列 -  0
  -  1
  -  2
  -  3
  -  4
 

而我想要得到这样的： -

 阵列
      BASE_PATH  -  /路径/要/项目
      DB_HOST  - 本地主机
      DB_NAME  - 数据库
      DB_USER  - 根
      DB_PASS  - 根
 

解决方案

您应该调试你的 PHP脚本第一家生产有效阵列的内容，code

 打印$ associativeArray;
 

只会让你的输出如下：

  $ PHP test.php的
排列
 

您可以简单地打印关联数组在foreach循环：

 的foreach（$ associativeArray为$关键=＆GT; $ VAL）{
    回声$键：$ VAL \\ N的;
}
 

让变量名称由+内容分隔列表：

  $ PHP test.php的
BASE_PATH：1
DB_HOST：2
DB_NAME：3
DB_USER：4
DB_PASS：5
 

---

至于在 shell脚本，我建议使用的简单易懂的外壳构造的，然后获取到高级的（如 $ {＃结果} ）正确地使用它们。

我曾尝试以下bash脚本摆脱PHP脚本输出变量shell脚本：

 ＃设置读取COMAND字段分隔符
IFS =：＃解析PHP脚本，通过读命令的输出
PHP的$ PWD'/ test.php的'|而阅读-r关键VAL;做
    回声$键= $ VAL
DONE
 

I am a newbie with shell scripts and I learnt a lot today. This is an extension to this question Assigning values printed by PHP CLI to shell variables

I got the solution to read a variable in my shell script. Now how to manipulate an array? If I prepare an array in my PHP code and print it, and echo in my shell, it displays Array. How to access that array in the shell script? I tried the solution given in how to manipulate array in shell script

With the following code:-
PHP code

$neededConstants = array("BASE_PATH","db_host","db_name","db_user","db_pass");

$associativeArray = array();
foreach($neededConstants as $each)
{
    $associativeArray[$each] = constant($each);
}

print $associativeArray;

Shell code

function getConfigVals()
{
    php $PWD'/developer.php'
}




cd ..
PROJECT_ROOT=$PWD
cd developer

# func1 parameters: a b
result=$(getConfigVals)

for((cnt=0;cnt<${#result};cnt++))
do
    echo ${result[$cnt]}" - "$cnt
done

I get this output:-

Array - 0
 - 1
 - 2
 - 3
 - 4

Whereas I want to get this:-

Array
      BASE_PATH - /path/to/project
      db_host - localhost 
      db_name - database
      db_user - root 
      db_pass - root

解决方案

You should debug your PHP script first to produce the valid array content, code

print $associativeArray;

will just get you the following output:

$ php test.php 
Array

You can simply print the associative array in a foreach loop:

foreach ( $associativeArray as $key=>$val ){
    echo "$key:$val\n";
}

giving a list of variable names + content separated by ':'

$ php test.php 
BASE_PATH:1
db_host:2
db_name:3
db_user:4
db_pass:5

---

As for the shell script, I suggest using simple and understandable shell constructs and then get to the advanced ones (like ${#result}) to use them correctly.

I have tried the following bash script to get the variables from PHP script output to shell script:

# set the field separator for read comand
IFS=":"

# parse php script output by read command
php $PWD'/test.php' | while read -r key val; do
    echo "$key = $val"
done

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