如何定义实例模型在 Rails 6 中的呈现方式 [英] How to define the way instance model should be rendered in Rails 6

问题描述

我正在使用 Hotwire 并在 Rails 6.0.3.6 应用程序上设计用户.

I'm using Hotwire and devise User on a Rails 6.0.3.6 app.

我为用户添加此广播

class User    
  after_create_commit { broadcast_append_to 'users' }
end

然后当一个用户被创建时，它会通过他的部分(users/user)，在那里我试图使用 current_user 设计助手.

Then when a User is created it goes through his partial (users/user) where I am trying to use current_user Devise helper.

但是 Rails 抛出这个错误:

But Rails throw this error:

Devise::MissingWarden in Players::Registrations#update
Devise could not find the `Warden::Proxy` instance on your request environment.
Make sure that your application is loading Devise and Warden as expected and that the `Warden::Manager` middleware is present in your middleware stack.

也许解决方案是能够告诉 Rails 以下内容:

Maybe the solution would be to be able to tell Rails the following:

如果从模型中，您试图渲染他的默认部分 (.to_partial_path)，您需要向它传递一些局部变量，例如 user: self.

If from a model, you are trying to render his default partial (.to_partial_path) you need to pass it some locals variables,like user: self.

我怎么能这样对 Rails 说?

How could I say that to Rails ?

谢谢你的帮助

推荐答案

DHH 说:

用于 Turbo 流的部分必须是全局的引用，因为它们是由 ApplicationRenderer 呈现的，而不是在特定请求的上下文.

Partials used for turbo streaming have to be free of global references, as they’re rendered by the ApplicationRenderer, not within the context of a specific request.

https://discuss.hotwire.dev/t/authentication-and-devise-with-broadcasts/1752/4

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