JavaScript的比较数组 [英] JavaScript compare arrays

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本文介绍了JavaScript的比较数组的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我在以下格式的数组:

var markers = [
    ['Title', 15.102253, 38.0505243, 'Description', 1], 
    ['Another Title', 15.102253, 38.0505243, 'Another Description', 2],
    ['Title 3', 15.102253, 38.0505243, 'Description 3', 3], 
];

然后我有被传递到页面(M = 1,2),这被逗号分隔的查询字符串,然后分割创建类似如下的数组:

I then have a query string being passed to the page (m=1,2), which being comma separated, is then split to create an array like the following:

['1', '2']

我需要做的是找到所有的'标志',其中ID(标记[I] [4])来自查询字符串。

What I need to do is find all 'markers' where the ID (markers[i][4]) comes from the query string.

什么是实现这一目标的最佳途径?理想我想创建相同的格式为标记,但只显示从查询字符串结果的第三个阵列。

What would be the best way to achieve this? Ideally I want to create a 3rd array in the same format as 'markers' but only showing the results from the query string.

任何帮助将大大AP preciated。

Any help would be greatly appreciated.

感谢

推荐答案

一种选择是使用嵌套循环:

One option is to use nested loops:

var markers = [
    ['Title', 15.102253, 38.0505243, 'Description', 1], 
    ['Another Title', 15.102253, 38.0505243, 'Another Description', 2],
    ['Title 3', 15.102253, 38.0505243, 'Description 3', 3], 
];
var search = ['1', '2'];
var result = [];

for (var i = 0; i < search.length; i++)
    for (var j = 0; j < markers.length; j++)
        if (search[i] == markers[j][4]) {
            result.push(markers[j]);
            break;
        }

console.log(result);

DEMO: http://jsfiddle.net/3TErD/

这篇关于JavaScript的比较数组的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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