将 combinelatest 触发其子节点的 doOnUnsubscribe [英] Will combinelatest trigger doOnUnsubscribe of its children

问题描述

不确定组合的可观察委托是否取消订阅其来源.

Not sure if the combined observable delegates doonunsubscribe to its sources.

如果没有，是否有一种简单的方法来触发其子项的取消订阅?

If not is there a simple way to trigger the unsubscribles of its children?

在代码中:

observable o = observable.combinelatest(o1, o2);

如果某事触发取消订阅 o 会触发取消订阅 o1 和 o2 吗?

If something triggers unsubscribe of o will it trigger the unsubscribe of o1 and o2?

推荐答案

不确定你的意思.

取消订阅被传播到 o1 和 o2 但如果你想执行自定义操作，你必须在所有相关方上使用 doOnUnsubscribe:

Unsubscription is propagated to both o1 and o2 but if you want to perform custom actions, you have to use doOnUnsubscribe on all relevant parties:

Observable<T> o = Observable.combineLatest(
    o1.doOnUnsubscribe(() -> { }),
    o2.doOnUnsubscribe(() -> { }))
.doOnUnsubscribe(() -> { });

o.take(1).subscribe();

但请注意，这些是全局链(而不是每个订阅者)的操作，对 o 的第二次订阅/取消订阅可能会再次调用它们.如果您需要按订阅者进行资源管理，请查看 using 运算符.

But note that these are chain-global (instead of per-subscriber) actions and a second subscription/unsubscription to o may call them again. If you need per-subscriber resource management, look at the using operator.

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