xsl:复制除父节点之外的整个xml但保留其子节点 [英] xsl: Copy the entire xml except a parent node but keep its child node

问题描述

我想复制整个 XML 文档但删除一个父节点.但是，这个父节点还有一个我想保留的子节点.

I want to copy the entire XML document but remove a parent node. However this parent node also has a child that I'd like to keep.

要删除的节点是，要保留的子节点是.

The node to remove is <LoginID> and the child node to keep is <PAN>.

<InqRs>
    <LoginID>                <!-- remove -->
        <PAN>4506445</PAN>   <!--  keep  -->
    </LoginID>
    <RqUID>93</RqUID>
    <Dt>90703195116</Dt>
    <CaptureDate>704</CaptureDate>
    <ApprovalCode>934999</ApprovalCode>
    <StatusCode>000</StatusCode>
    <List>
        <Count>9</Count>
        <AddDataFlag>N</AddDataFlag>
        <Use>C</Use>
        <DetRec>
            <ID>007237048637</ID>
            <Type1>62</Type1>
            <Qual />
            <ID>0010</ID>
            <Status>1</Status>
            <InqFlag>Y</InqFlag>
        </DetRec>
    </List>
</InqRs>

推荐答案

这个 XSL 应该能满足需要.

This XSL should do the needful.

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" indent="yes"/>
<xsl:template match="*">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>   
<xsl:template match="InqRs/LoginID">
      <xsl:copy-of select="@*|node()" />    
  </xsl:template>
</xsl:stylesheet>

这篇关于xsl:复制除父节点之外的整个xml但保留其子节点的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！