找到一个字符串到字符串数组最快的方法 [英] Fastest way to find a String into an array of string

问题描述

该脚本来验证，如果一个predefined IP是IP地址的一个大数组present。目前我code的功能类似这样（说IPS是我的IP阵列和IP是predefined IP）

The script has to verify if one predefined IP is present in a big array of IPs. Currently I code that function like this (saying that "ips" is my array of IP and "ip" is the predefined ip)

ips.each do |existsip|
  if ip == existsip
    puts "ip exists"
    return 1
  end
end
puts "ip doesn't exist"
return nil

有没有更快的方式做同样的事情？

Is there a faster way to do the same thing?

编辑：我可能有错误的前pressed自己。我可以做array.include？但我想知道的是：是array.include？这将使我最快结果的方法？

Edit : I might have wrongly expressed myself. I can do array.include? but what I'd like to know is : Is array.include? the method that will give me the fastest result?

推荐答案

您可以使用的设置。这是哈希的基础上实现，将是更快的数据集大 - O（1）

You can use Set. It is implemented on top of Hash and will be faster for big datasets - O(1).

require 'set'
s = Set.new ['1.1.1.1', '1.2.3.4']
# => #<Set: {"1.1.1.1", "1.2.3.4"}> 
s.include? '1.1.1.1'
# => true 

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