使用替换映射替换字符串上的多个单词 [英] Replace multiple words on string using Map of replacements

问题描述

我有一张替换地图

val 替换 = Map( "aaa" -> "d", "bbb" -> "x", "ccc" -> "mx")

我想用相应的值替换字符串中所有出现的每个映射键.

I would like to replace all occurrences of each map key in the string with the corresponding value.

val str = "This aaa is very bbb and I would love to cccc"
val result = cleanString(str, replacements)
result = "This d is very x and I would love to mx"

我已经完成了

val sb = new StringBuilder(str)
for(repl <- replacements.keySet) yield {
  sb.replaceAllLiterally(repl, replacement.get(repl))
}

但我想要一些功能更强大的东西，比如 map 或 fold，其中我应用于字符串的函数返回另一个字符串，而无需在内部修改的可变变量循环.

but I would like something more functional like a map or fold where the function I apply to the string returns another string without needing a mutable variable that is modified inside the loop.

推荐答案

一个选项:在 Map 上使用 foldLeft 和 str 作为初始参数:

One option: use foldLeft on the Map with str as the initial parameter:

replacements.foldLeft(str)((a, b) => a.replaceAllLiterally(b._1, b._2))
// res8: String = This d is very x and I would love to mxc

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