将 5 个温度从华氏度转换为摄氏度 [英] converting 5 temperatures from fahrenheit to celsius

问题描述

每天，气象站都会收到 5 个以华氏度表示的温度.编写一个接受华氏温度的程序，将其转换为摄氏温度并在屏幕上显示转换后的温度.5 次温度后，屏幕上应显示消息所有温度已处理"

Every day, a weather station receives 5 temperatures expressed in degree Fahrenheit. Write a program to accept temperature in Fahrenheit, convert it to Celsius and display the converted temperature on the screen. After 5 temperatures, the message ‘All temperatures processed’ should be displayed on the screen

我的回答如下

#include <stdio.h>
main()
{
  int fah, cel;
  printf("\nEnter 5 temperatures in Fahrenheit: ");
  scanf("%d %d %d %d %d", &fah);
  do
  { 
    cel=(fah-32)*(5/9);
    printf("\n These temperatures converted to Celsius are: %d \n", cel);
  }
  while(fah);
}

推荐答案

让我们一一解决 -

• scanf("%d %d %d %d %d", &fah); :你想扫描五个值，而你只使用一个 %d.其他四个值呢?您应该使用包含 5 个值的数组.
• cel=(fah-32)*(5/9); :您将 5 除以 9，这两个都是整数.一个整数除以另一个的结果，a/b，其中 a cel 将始终为 0.您必须将整数之一转换为浮点数/双精度数.
• 如果您确实使用数组，则需要遍历数组的所有元素来处理它们.

• scanf("%d %d %d %d %d", &fah); : You want to scan five values while you are using only one %d. What about the other four values ? You should use an array of 5 values.
• cel=(fah-32)*(5/9); : You are dividing 5 by 9, both of which are integers. The result of dividing an integer by another, a/b, where a < b is 0. Hence cel will always be 0. You have to cast one of the integers to a float/double.
• If you do use an array, you need to loop over all elements of the array to process them.

我故意不提供所有这些的直接解决方案.我建议您查看并理解这些内容，因为它们是 C 编程的基础.

I am purposely not providing a direct solution to all these. I suggest you look up on these things and understand them, since they are very basic for programming in C.

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